Answer:
B
Explanation:
Animals, plants, and fungi are multicellular organisms so therefore B
Answer:
whether these DNA tests can tell us much about an individual newborn's destiny, they are already a useful research tool that is providing new insights into how genes and environments interact, new avenues for understanding how mental illnesses (and other illnesses) develop and new pathways to explore potential ...
hope this will help you
mark me brainliest
Well I think I might know this since I was born and grew up in WI, but don't be 100% dependent with my answer because I'm only in 7th grade and I am doing high school stuff. Well my guess is the proportion of the genes is 1/2 because when a offspring is produced the genes are split from each parent rather its a human baby, a mammal, a fish, a reptile, a insect, or a plant. Although, I don't know what f1 means except for it being a control on the computer lol. But like I said I'm only in 7th grade so I don't know everything but I'm smarter than a average 7th grader.
Hope this helps! (it probably wont though)
Water, Humus, air, plants, organisms , nutrients, particles (inorganic
Answer:
1. Allele frequency of b = 0.09 (or 9%)
2. Allele frequency of B = 0.91 (0.91%)
3. Genotype frequency of BB = 0.8281 (or 82.81%)
4. Genotype frequency of Bb = 0.1638 (or 16.38%)
Explanation:
Given that:
p = the frequency of the dominant allele (represented here by B) = 0.91
q = the frequency of the recessive allele (represented here by b) = 0.09
For a population in genetic equilibrium:
p + q = 1.0 (The sum of the frequencies of both alleles is 100%.)
(p + q)^2 = 1
Therefore:
p^2 + 2pq + q^2 = 1
in which:
p^2 = frequency of BB (homozygous dominant)
2pq = frequency of Bb (heterozygous)
q^2 = frequency of bb (homozygous recessive)
p^2 = 0.91^2 = 0.8281
2pq = 2(0.91)(0.9) = 0.1638
