Multicellular is the word you're looking for ;-)
Answer:
Following are the responses to these question:
Explanation:
The heterokaryons were cells of diverse traditions or more nuclei. A heterokaryon cell with network cells (donor and receiver nuclei) sharing a common costly to treat is produced whenever a node containing GFP-tagged protein (donor cell) is merged to a cell non express the GFP-tagged proteins (recipient cell). Unless the intracellular scram nuclear exists, GFP must leave the GFP atoms, be shipped to the cytosol, and be exported to a nucleus with emission of GFP protein (recipient nucleus). It is obtaining nuclear has been beginning to release the GFP protein.
Unless the GFP protein doesn't display a nucleus costly to treat, this is not distributed across time in the metal target. By either sole dissemination through nuclear pores or receptor-mediated routes, protein yelling from nuclear to emotional exhaustion can occur. That GFP proteins are shown in a nucleus only suggests a path via a transmitter. For chloroplast, though, protein disperses via nuclear envelope. It is not the case. It should have nuclear foreign trade signals when ferrying between the nucleus and cytoplasm.
Cycloheximide is indeed a medicine that stops protein expression without elongating. For heterokaryon cells, it inhibits fresh protein synthesis. It makes visualization of a nanoparticle cell of only old pre-existing molecules (before cycloheximide diagnosis). That post GFP substance is a shuttling shielding substance that passes seen between the nucleus and the cytoplasm and the receiver nucleus. Whenever the levels of the shuttle were high, the GFP protein expression is shown both by the sender and receiver nucleus. The recipient nucleus will not be left without any schlepping protein. Thus, the donor nucleus can only be used.
Answer:
The correct answer is b) When a plant cell is placed in concentrated salt water, water moves out of the cell.
Explanation:
Osmosis is the movement of solvent molecules from an area of less concentration of solute to high concentration of solute to equalize the concentration of both the side of the cell.
So water will move outside the cell when any cell will be placed in a concentrated salt water because the concentration of solute is high in salt water and low inside the cell.
Therefore when a plant cell is placed in salt water the osmosis of water takes place from inside to outside the cell. So the right answer is b.
Answer:
The glucose conversion to PYRUVATE opens anaerobic and aerobic metabolic pathways. VITAMIN B NIACIN in its role as a coenzyme during glycolysis, escorts hydrogen and electrons to the electron transport chain and the TCA cycle. In the Cori cycle, the release of energy from ATP converts lactate to glucose and returns the glucose molecule to the muscles through the process of Anaerobic Glycolysis.
Explanation:
In metabolism, glycolysis is defined as the splitting of the glucose molecule to form two molecules of pyruvic acid. It is the first main metabolic pathway in cellular respiration for the production of energy in form of ATP(Adenosine triphosphate).
In most cells, cellular respiration occurs in the presence of oxygen. This is known as AEROBIC RESPIRATION which produces the largest number of ATP. Energy can also be gotten by breaking down of glucose in the complete absence of oxygen. This is known as ANAEROBIC RESPIRATION.
The next stage in the degradation of glucose is a two step conversion of the two pyruvic acid molecules from glycolysis into two molecules of acetyl coenzyme A( acetyl - CoA). This occurs in the TCA( tricarboxylic acid) or Krebs cycle.
VITAMIN B NIACIN in its role as a coenzyme during glycolysis, escorts hydrogen and electrons to the electron transport chain and the TCA cycle. Coenzyme A is a derivative of vitamin B which combines with pyruvic acid to form acetyl CoA , 2 molecules of carbon dioxide and 4 molecules of hydrogen in TCA cycle.
In Cori Cycle, (which is also called Lactic acid cycle), energy released from ATP is used to convert lactate to glucose. This is to prevent increased lactic acid in the blood during anaerobic conditions in the muscles.
While giving birth to her infant during labor, the safest and the most effective pushing technique taught to a woman during contractions is grasping knees, head elevated and breathing out.
During labor, it is very important for the mother to keep breathing. If she holds her breath, it will put pressure on the vena cava and lead to a reduction in the blood return. The head is kept elevated and the back is rounded which aids the abdominal muscles to help the uterus to push the baby out. Grasping the knees also helps in pushing and encouraging the movement of the infant outside the body.
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