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4 years ago

8

If a point on the pre-image has coordinates (3, -4), and the coordinates of its image are (12, -16), what scale factor was used

for the dilation?

2 answers:

just olya [345]4 years ago

8 0

A scale factor of 4. This is a simple dilation problem.

Shkiper50 [21]4 years ago

5 0

Answer:

The correct answer is: 4

Step-by-step explanation:

I hope this helps! :)

Plz mark brainliest, trying to rank up!

Have a nice day!

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A birthday cake was cut into equal pieces, and four pieces were eaten. The fraction below shows how many pieces were left. Accor

zmey [24]

4 were not eaten from the cake

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4 years ago

How do you do this please explain too if you can.

elena-s [515]

Add 2500G and 1250G and you get 3750

divide by 6 and you get 625
answer 625

6 0

3 years ago

Is the answer a, b, c, or d?

Arlecino [84]

17 is my answer. Make sure to study all the material before taking any major Test or Quizzes.

Happy studying ^-^

3 0

3 years ago

.4^3Grafting, the uniting of the stem of one plant with the stem or root of another, is widely used commercially to grow the ste

11111nata11111 [884]

Answer:

0.784 = 78.4% probability that there will be at least one failed graft in the next three done

Step-by-step explanation:

To solve this question, we need to understand the binomial probability distribution and conditional probability.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: No failed grafts in the first seven

Event B: At least one fail in the next three.

Intersection of events A and B:

Since the probability of a graft failling is independent of other grafts, we have that:

$P(A \cap B) = P(A)*P(B)$

So

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{P(A)*P(B)}{P(A)} = P(B)$

So we just have to find the probability of one fail in three trials.

Three trials means that $n = 3$ .

The probability is

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{3,0}.(0.4)^{0}.(0.6)^{3} = 0.216$

Then

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.216 = 0.784$

0.784 = 78.4% probability that there will be at least one failed graft in the next three done

3 0

3 years ago

What is the constant of proportionality for the following table? Express your answer as a decimal.

stellarik [79]

Answer:

Bottom is 1 Top is 2 I guess

6 0

3 years ago