The equation that pases through these sets of points would be
y = 2x + 3
The slope of the equation is 2, and the y-intercept is 3.
So then we do
large-small
V=(1/3)hpir^2
given
small=r=3 and h=5
V=(1/3)5pi3^2
V=5pi3
V=15pi
large, r=5, h=12
V=(1/3)5pi12^2
V=5pi48
V=240pi
large-small=240pi-15pi=225pi in^3
aprox 706.8582 in^3
Answer:
a. x^2+2xy+y^2
Step-by-step explanation:
I hope this helps
Answer:
a = -2/3
Step-by-step explanation:
Solve for a over the real numbers:
(3 a + 2) (4 a^2 - 2 a + 9) = 0
Split into two equations:
3 a + 2 = 0 or 4 a^2 - 2 a + 9 = 0
Subtract 2 from both sides:
3 a = -2 or 4 a^2 - 2 a + 9 = 0
Divide both sides by 3:
a = -2/3 or 4 a^2 - 2 a + 9 = 0
Divide both sides by 4:
a = -2/3 or a^2 - a/2 + 9/4 = 0
Subtract 9/4 from both sides:
a = -2/3 or a^2 - a/2 = -9/4
Add 1/16 to both sides:
a = -2/3 or a^2 - a/2 + 1/16 = -35/16
Write the left hand side as a square:
a = -2/3 or (a - 1/4)^2 = -35/16
(a - 1/4)^2 = -35/16 has no solution since for all a on the real line, (a - 1/4)^2 >=0 and -35/16<0:
Answer: a = -2/3
The relationship between the 4s is that the first 4 is in the thouand's place and the second 4 is in the hundred's place
