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ollegr [7]
3 years ago
5

Simplify. 2x120x20 0 4x²/5 4x" 5 2x "/10

Mathematics
2 answers:
NARA [144]3 years ago
5 0

<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3

Answer:

4x ^ 11 sqrt 5

<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3

solniwko [45]3 years ago
5 0

Answer:

4x^11 \sqrt{5}

Step-by-step explanation:

You can simplify the 20 inside of the radical by finding its prime factors. 20 has 3 prime factors: 5, 2, and 2. Since the 2 occurs twice, we can cancel out those 2s in the 20 itself and put a singular 2 outside of the radical. It is essentially turning \sqrt{20} into 2\sqrt{5}. Since we now have simplified that 20, the entire equation is now 4x\sqrt{5x^2^0}. We can root x^20 to get x^10, and \sqrt{5} stays that way. The entire equation is now 4x\sqrt{5}x^10, which can be simplified to 4x^1^1\sqrt{5}.

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2 years ago
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Explain: What is the solution to this system of equations? <br><br> 2x+y=20 <br> 6x-5y=12
bazaltina [42]

Answer:

solution set is (x,y) = (7,6)

Step-by-step explanation:

solving by substitution method

2x +y=20--------------1

6x-5y=12---------------2

from equation 1, solve for y

2x+y=20

y= 20-2x------equation 3

adding value of y in equation 2

6x-5y=12

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3 0
3 years ago
50,000 contestants participate in an on-line game. The game randomly eliminates 20% of the contestants each day. Determine the n
irga5000 [103]

Answer:10,486 contestants

Step-by-step explanation:

First day:

Total number of contestants at the beginning = 50,000

After first day, 20% 0f 50,000 are removed.

That is, (20/100)×50,000 = 10,000

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Second day:

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Fifth day:

Contestants= 20,480

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That is (20/100)×20,480=4096

Balance =20,480-4096=16,384

Sixth day:

Contestants= 16,384

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That is (20/100)×16,384=3276.8

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Seventh day:

Contestants= 13,107.2

20% removed

That is (20/100)×13,107.2=2621.44

Balance =13107.2-2621.44=10485.76

Therefore, number of contestants remaining after one week equals 10,486.

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