If x is the first of the integers then the statement is:
(x) , (x+2) , (x+4) , (x+6)
This means that the smallest is x and the largest is x + 6
so:
3(x) + 2(x+6) = 293
3x + 2x + 12 = 293
5x = 281
x = 56.2
This gives us a none integer (decimal)
What now?
Wait remember how x started as the lowest? what if x was the highest instead?
x, x-2, x-4, x-6
so:
3(x-6) + 2(x) = 293
5x = 315
x = 62.2
This is as close as have gotten to the answer
Cant seem to get an integer.
Maybe error in the question or some bad math on my part.
This is similar to the other question you posted. Follow the same steps as before.
First find g(41).
g(41) = sqrt{x - 5}
g(41) = sqrt{41 - 5}
g(41) = sqrt{36}
g(41) = 6
We now find f(6).
f(6) = -7(6) + 1
f(6) = -42 + 1
f(6) = -41
Answer:
(fºg)(41) = -41
Did you follow?
Answer:
The slope of the line passing through the points (−3, −5) and (−1, −6) is
(-0.5)
Step-by-step explanation:
Equation of a straight line:
y = mx + b where m is the slope and b is the y-intercept
(x1, x2) and (y1, y2) : (−3, −5) and (−1, −6)
Calculating Slope (m).
m = 
m = 
m = 
m = 
we can take this a step further by finding the equation:
Now putting value of m in equation (i)
y = -0.5x + b
Calculating Y-intercept (b).
Lets choose the first point, (-3,-5) for calculating y-intercept:
y = mx + b
-5 = -0.5(-3) + b
-5 = 1.5 + b
-6.5 = b
b = -6.5
Now putting value of b in equation
y = -0.5x + -6.5