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ehidna [41]
3 years ago
10

Which of the following plantonic solids is also a cube?​

Mathematics
1 answer:
34kurt3 years ago
4 0

Answer:

Hexahedron

Step-by-step explanation:

A cube is a regular hexahedron, as both the hexahedron and the cube have 6 faces, and a hexhedron can sometimes be a cube.

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In a 1-mile race, the winner crosses the finish line 10 feet ahead of the second-place runner and 23 feet ahead of the third-pla
GuDViN [60]
5280 - 10 = 5270 ft, traveled by the 2nd place runner
5280 - 23 = 5257 ft, traveled by the 3rd place runner
 Use a ratio equation5280/5270    =    x/5257
 Cross multiply:
5270x = 5280 * 5257x
= 27756960/5270x
= 5266.975 traveled by the 3rd place runner when the 2nd place runner crosses the finish line.
5280 - 5266.975
= 13.025 ft is the distance the 2nd place runner beats the 3rd place runner.
This makes sense because they were 13 ft apart when the winner crossed the line, the 3rd place runner is 13 ft behind the 2nd runner because he runs slower.
8 0
3 years ago
What is the height??
Mashutka [201]

Answer:

72 is the height..........

7 0
3 years ago
A phone plan charges $15.95 per month and $0.10 for every minute, m, that the phone is used. Mr. Kordemsky wants his phone bill
aleksandrvk [35]

Answer:

The inequality that could be used to model this situation is 15.95+0.10m<40. Also, the number of minutes has to be less than 240.5 for Mr. Kordemsky's phone bill for the month to be less than $40.

Step-by-step explanation:

From the information provided, the inequality would indicate that the phone bill for the month that is equal to the result of the fixed fee plus the price per minute for the number of minutes has to be less than $40, which can be expressed as:

15.95+0.10m<40

Now, you can solve for m:

15.95+0.10m<40

0.10m<40-15.95

0.10m<24.05

m<24.05/0.10

m<240.5

According to this, the answer is that the inequality that could be used to model this situation is 15.95+0.10m<40. Also, the number of minutes has to be less than 240.5 for Mr. Kordemsky's phone bill for the month to be less than $40.

6 0
3 years ago
Can you help me to solve this<br>​
RUDIKE [14]

Answer:

Is the question even complete ?

Step-by-step explanation:

5 0
2 years ago
Determine whether each of these sets is nite, countably in nite, or uncount- able. For those that are countably in nite, exhibit
ira [324]

Answer:

Integers that are divisible by 7 are countably infinite

The set are {7, 14, 21, 28, 35, 42, 49,......

Integers that are divisible by 10 are countably infinite

The set are {10, 20, 30, 40, 50, 60, 70,........

Also for the negative integers divisible by 7 or 10{.......,-49, -42, -35, -28, -21, -14, -7} or {........,-70, -60, -50, -40, -30, -20, -10} are countably infinite

Step-by-step explanation:

See the set of integers divisible by 7 or 10,

{7, 14, 21, 28, 35, 42, 49,........} Or

{10, 20, 30, 40, 50, 60, 70,.......}

Can be map one-to-one to {1,2,3,4,5,6,7,...... The set of natural numbers or positive Integers.

So also, it is applicable in negative integers divisible by 7 or 10.

Therefore, they are countably infinite

A set is uncountable if it contains so many elements that they cannot be put in one-to-one correspondence with the set of natural numbers(Positive Integers). In other words, there is no way that one can count off all elements in the set in such a way that, even though the counting will take forever, you will get to any particular element in a finite amount of time.

WHILE

A set is countable or countably finite if it contains so many elements that they CAN be put in one-to-one correspondence with the set of natural numbers(Positive Integers)

3 0
3 years ago
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