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3 years ago

6

Lara made some chocolate tarts. For every 5 cups of chocolate chips. She added 3 cups of sugar. The ratio of chocolate chips to

sugar in Lara's chocolate tarts is

1 answer:

aliya0001 [1]3 years ago

5 0

5 chocolate chips: 3 cups of sugar

Hope this helps!

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The height of a triangle is two more than three times the base. Determine the dimensions that will give a total area of 28 yards

jonny [76]

H = 3b+2
A = (h*b)/2 28 = (3b+2)b/2 56 = 3b²+2b 0 = 3b² + 2b - 56

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8 0

3 years ago

A patient drinks 5 12ounce cups of coffee daily. The doctor recommends cutting back 60%, how many ounces of coffee can the patie

maksim [4K]

The patient is recommended to take 24 ounces of coffee per day.

<u>Step-by-step explanation:</u>

Patient normal intake of coffee daily = 5 times 12 ounces

= 5 × 12 = 60 ounces

Doctor recommends to cut off 60 % of the normal intake of coffee.

And advised to take only 40 % of the daily intake of coffee.

So 60 % of 60 ounces can be calculated as,

$$\frac{60 \times 60}{100}$ = 36 ounces

40 % of 60 ounces is 24 ounces.

So 60 - 36 = 24 ounces of coffee per day

6 0

2 years ago

T 11 is 12% of what number?

zmey [24]

Answer:

88

Step-by-step explanation:

12.5% is the same as 1/8 of something

11*8=88

5 0

1 year ago

Find the perimeter of the pentagon MNPQR with vertices M(2, 4), N(5, 8), P(8, 4), Q(8, 1), and R(2, 1)

Gekata [30.6K]

Answer:

The pentagon MNPQR has a perimeter of 22 units.

Step-by-step explanation:

Geometrically speaking, the perimeter of the pentagon is the sum of the lengths of each side, that is:

$p = MN + NP + PQ + QR + RM$ (1)

$p = \sqrt{\overrightarrow{MN}\,\bullet \, \overrightarrow{MN}} + \sqrt{\overrightarrow{NP}\,\bullet \, \overrightarrow{NP}} + \sqrt{\overrightarrow{PQ}\,\bullet \, \overrightarrow{PQ}} + \sqrt{\overrightarrow{QR}\,\bullet \, \overrightarrow{QR}} + \sqrt{\overrightarrow{RM}\,\bullet \, \overrightarrow{RM}}$ (1b)

If we know that $M(x,y) = (2,4)$ , $N(x,y) = (5,8)$ , $P(x,y) = (8,4)$ , $Q(x,y) = (8,1)$ and $R(x,y) = (2,1)$ , then the perimeter of the pentagon MNPQR is:

$p =\sqrt{(5-2)^{2}+(8-4)^{2}} + \sqrt{(8-5)^{2}+(4-8)^{2}}+\sqrt{(8-8)^{2}+(1-4)^{2}}+\sqrt{(2-8)^{2}+(1-1)^{2}}+\sqrt{(2-2)^{2}+(4-1)^{2}}$ $p = \sqrt{3^{2}+4^{2}} + \sqrt{3^{2}+(-4)^{2}}+\sqrt{0^{2}+(-3)^{2}}+\sqrt{(-6)^{2}+0^{2}}+\sqrt{0^{2}+3^{2}}$

$p = 22$

The pentagon MNPQR has a perimeter of 22 units.

4 0

2 years ago

Can someone please helppp will give you lots of points and brainliest

harkovskaia [24]

4. SOLVE FOR X:

Using the Alternate Interior Angles Theorem, we know that the 67 degree angle is congruent with the (12x - 5) degree angle. With this information, all I have to do is set the two equal to each other and solve for x.

67 = 12x - 5

67 + 5 = 12x - 5 + 5

72/12 = 12x/12

6 = x

x = 6

SOLVE FOR Y:

Using the Vertical Angles theorem, we know that angle y must be congruent to the 67 degree angle.

y = 67 degrees.

5. SOLVE FOR Y:

Alternate exterior angles: 6(x - 12) = 120

6x - 72 + 72 = 120 + 72

6x/6 = 192/6

x = 32

SOLVE FOR Y:

6((32) - 12) + y = 180

192 - 72 + y = 180

120 + y - 120 = 180 - 120

y = 60

8 0

3 years ago

Read 2 more answers