Let's solve this problem step-by-step.
First of all, let's establish that supplementary angles are two angles which add up to 180°.
Therefore:
Equation No. 1 -
x + y = 180°
After reading the problem, we can convert it into an equation as displayed as the following:
Equation No. 2 -
3x - 8 + x = 180°
Now let's make (y) the subject in the first equation as it is only possible for (x) to be the subject in the second equation. The working out is displayed below:
Equation No. 1 -
x + y = 180°
y = 180 - x
Then, let's make (x) the subject in the second equation & solve as displayed below:
Equation No. 2 -
3x - 8 + x = 180°
4x = 180 + 8
x = 188 / 4
x = 47°
After that, substitute the value of (x) from the second equation into the first equation to obtain the value of the other angle as displayed below:
y = 180 - x
y = 180 - ( 47 )
y = 133°
We are now able to establish that the value of the two angles are as follows:
x = 47°
y = 133°
In order to determine the measure of the bigger angle, we will need to identify which of the angles is larger.
133 is greater than 47 as displayed below:
133 > 47
Therefore, the measure of the larger angle is 133°.
There are 7 sides available.
The fundamental counting principal tells us to find the total number of combinations of independent items, multiply the number of choices from each one (choices x choices x....)
This means that drink x sides x sandwiches = 560. We know there are 16 sandwiches and 5 drinks. Let S be the number of sides:
15(6)(S) = 560
80S = 560
Divide both sides by 80:
80S = 560/80
S = 7
Answer: i. There are 140 students willing to pay $20.
ii. There are 200 staff members willing to pay $35.
iii. There are 100 faculty members willing to pay $50.
Step-by-step explanation: Suppose there are three types of consumers who attend concerts at Marshall university's performing arts center: students, staff, and faculty. Each of these groups has a different willingness to pay for tickets; within each group, willingness to pay is identical. There is a fixed cost of $1,000 to put on a concert, but there are essentially no variable costs.
For each concert:
A) If the performing arts center can charge only one price, what price should it charge? What are profits at this price? B) If the performing arts center can price discriminate and charge two prices, one for students and another for faculty/staff, what are its profits?
C) If the performing arts center can perfectly price discriminate and charge students, staff, and faculty three separate prices, what are its profits?
We did this this year and by what I can remember I belive it is 4,320 inches. I hope this helps and I hope I got it right so u don't get it wrong.
Infinitely many, because if you simplified the right side, it would equal the left side.