The team first experiments with changing the position of the curved pit. In the computer program, the vertex begins on the origi
n, and the curve is modeled by the parent quadratic equation, y = x2. Match each description with the equation that will create that pit.
1 answer:
Answer:
Step-by-step explanation:
This question is incomplete; find the complete question in the attachment.
Given curve is modeled by the quadratic equation,
y = x²
If the curved pit is shifted 2 units down,
Equation of the translated curve will be,
y = x² - 2
If the curved pit is translated (shifted) by 2 units left,
Equation of the new curve will be,
y = (x + 2)²
If the curved pit is shifted by 2 units right,
Equation of the translated curve will be,
y = (x - 2)²
If the curved pit is shifted 2 units up,
Equation of the translated curve will be,
y = x² + 2
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→ a
the equation is y = mx ( where m is the slope / constant of variation )
calculate m using the gradient formula
m = ( y₂ - y₁ ) / (x₂ - x₁ )
with (x₁, y₁) = (0, 0 ) and (x₂, y₂ ) = (4, 1) ← 2 points on the line
m = =
Answer:
8/3 square units.
Step-by-step explanation:
First, visualize the area. You can refer to the attachment below.
To find the area then, we will integrate y from x = 0 to x = 2. Therefore:
Integrate:
Evaluate:
The area is 8/3 square units.
