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Yakvenalex [24]
3 years ago
12

Find the area of this triangle. Round the sine value to the nearest hundredth. Round the area to the nearest tenth of a centimet

er.
13.8 cm2

15.1 cm2

17.4 cm2

34.8 cm2

Mathematics
2 answers:
trasher [3.6K]3 years ago
8 0
Area = 1/2 * 7.2*6.4*sin49= 17.4cm^2
ivolga24 [154]3 years ago
8 0

Answer with Step-by-step explanation:

The area of a triangle when one angle a is given is given by:

A=\dfrac{1}{2}\times sina\times (Product\ of\ sides\ adjacent\ to\ angle\ a)

Here a=49 and sides adjacent to angle a are 7.2 and 6.4

A=\dfrac{1}{2}\times sin49\° \times 7.2\times 6.4\\\\A=\dfrac{1}{2}\times 0.75\times 7.2\times 6.4\\\\A=17.4\ cm^2

Hence, Area of given triangle is:

17.4 cm²

You might be interested in
Reduce to the simplest form. -9/6 + (-3/5)
creativ13 [48]

Answer:

-\frac{21}{10} or -2.1 (they're the same)

Step-by-step explanation:

  1. Simplify: -\frac{9}{6} + (-\frac{3}{5}) = -\frac{9}{6} - \frac{3}{5}  
  2. Find a common denominator. The LCM of 6 and 5 is 30, so multiply the numerator and the denominator by the same thing: 6 × 5 = 30, -9 × 5 = -45, 5 × 6 = 30, 3 × 6 = 18
  3. Write the new fractions: -\frac{45}{30} - \frac{18}{30}  
  4. Subtract: -45/30 - 18/30 = -\frac{63}{30} = -\frac{21}{10}

I hope this helps!

5 0
3 years ago
Which set of equations has (1, 2) as its solution?
FromTheMoon [43]
A and D... i think but i would rather go with A and C
4 0
3 years ago
A manufacturing facility produces rolls of tape. Among all of the rolls of tape produced, the mean length of the tape on a roll
Anna [14]

Answer:

P(\bar X< 651.1) =P(\bar X< \frac{651.1-651.25}{\frac{0.73}{\sqrt{78}}}= -1.815

And using the normal atandard table or excel we got:

P(z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Solution to the problem

Let X the random variable that represent the length of the tape of a population, and for this case we know the following parameters

Where \mu=651.25 and \sigma=0.73

We sselect a sample size of n =78>30. From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we want to find this probability:

P(\bar X< 651.1) =P(\bar X< \frac{651.1-651.25}{\frac{0.73}{\sqrt{78}}}= -1.815

And using the normal atandard table or excel we got:

P(z

8 0
2 years ago
Sharon went to the mall and purchased 4 pairs of jeans for $24.99 each, 1 pair of gym shoes for $125.57 and lunch for 15.93 the
alekssr [168]

Answer:

$226.97

Step-by-step explanation:

$24.99 x 4 = $99.96

$99.96 + $125.57 = $225.53

$225.53 + $15.93 = $241.46

$241.46 - 6% = $226.97

4 0
2 years ago
What is the median of the data?
UNO [17]
You need to order the data, so
11, 12, 13, 14, 14, 15, 17, 17, 18, 18, 18, 20
Then find the middle of the data. Because there are 12 data points, the median will lie between the two 6th placed numbers
The two numbers are 15 and 17, so work out the mean of them. (15+17)/2 = 16
So the answer is B. 16
3 0
3 years ago
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