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KengaRu [80]
3 years ago
14

Quadratic factorisation Question, help please.

Mathematics
1 answer:
Anna [14]3 years ago
8 0
The answer to your question is (3x+2)(x+1)
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Identify the vertex, roots, and equation of the function below.
spayn [35]

The equation of a parabola in vertex form, is:

y=a(x-h)^2+k

Where <em>(h,k)</em> are the coordinates of the vertex.

From the given graph, notice that the coordinates of the vertex are:

(5,6)

The roots are the values of <em>x</em> where the graph crosses the x-axis. In this case, the graph crosses the x-axis at the points <em>(4,0)</em> and <em>(6,0).</em> Then, the roots are:

\begin{gathered} x_1=4 \\ x_2=6_{}_{} \end{gathered}

Substitute the values of the vertex into the equation of the parabola in vertex form:

y=a(x-5)^2+6

To find the value of <em>a</em>, substitute <em>(x,y)=(4,0)</em>:

\begin{gathered} 0=a(4-5)^2+6 \\ \Rightarrow0=a(-1)^2+6 \\ \Rightarrow0=a+6 \\ \Rightarrow-6=a \\ \Rightarrow a=-6 \end{gathered}

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y=-6(x-5)^2+6

3 0
1 year ago
Please help! 70 points :)<br> Will award brainliest
dexar [7]

Answer:

38 = FH

Step-by-step explanation:

Because this is a rectangle, IG = FH

We know that IE + EG = FH

We also know that IE = EG   (perpendicular bisectors)

IE = EG

3x+4 = 5x-6

Subtract 3x from each side

3x-3x+4 = 5x-3x-6

4 = 2x-6

Add 6 to each side

4+6 =2x

10 =2x

Divide by 2

10/2 =2x/2

5=x


Now lets find FH

IE + EG = FH

3x+4 + 5x-6  = FH

Combine like terms

8x-2 = FH

Substitute in x =5

8*5-2

40-2

38 = FH

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Answer:

-2

Step-by-step explanation:

add 3 to 11 and then divide 14 by -7

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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