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fiasKO [112]
2 years ago
10

Review the graph of function f(x).

Mathematics
1 answer:
s344n2d4d5 [400]2 years ago
6 0

The two limits when x tends to zero are:

\lim_{x \to \ 0^-}  f(x) = 1\\\\ \lim_{x \to \ 0^+}  f(x) = 0

<h3 /><h3>How to get the limits when x tends to zero?</h3>

Notice that we have a jump at x = 0.

Then we can take two limits, one going from the negative side (where we will go along the blue line)

And other from the positive side (where we go along the orange line).

We will get:

\lim_{x \to \ 0^-}  f(x) = 1\\\\ \lim_{x \to \ 0^+}  f(x) = 0

Notice that the two limits are different, that means that the function is not a continuous function.

If you want to learn more about limits:

brainly.com/question/5313449

#SPJ1

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Jacob buys 3 hot dogs and a $1 soda.he spent $5.50 in all.what is the cost of one hot dog?
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It would be $1.50 because if the soda's $1 then subtract it and divide that by the quantity.
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3 years ago
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The general form of an parabola is 3x2+24x−2y+52=0.
DIA [1.3K]

Answer: 12x - y = -29

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What is the following simplified product? Assume x≥0. 2√8x^3(3√10x^4-x√5x^2)
natta225 [31]

i think the answer is A.

5 0
3 years ago
39. Solve this system: 3x+y=-7 . 4x-y=14A. (–1, 10)B. (1, –10)C. (–1, –10)D. no solution
valkas [14]

Given,

The linear pair of the equation is,

\begin{gathered} 3x+y=-7 \\ 4x-y=14 \end{gathered}

Required

The solution of the linear equation.

Taking the equation first as,

\begin{gathered} 3x+y=-7 \\ y=-7-3x \end{gathered}

Substituting the value of y in second equation then,

\begin{gathered} 4x-y=14 \\ 4x+7+3x=14 \\ 7x+7=14 \\ 7x=7 \\ x=1 \end{gathered}

Substituting the value of x in first equation then,

\begin{gathered} 3x+y=-7 \\ 3(1)+y=-7 \\ y=-7-3 \\ y=-10 \end{gathered}

Hence, the solution of the system is (1, -10).

8 0
1 year ago
What is the end point and mid point
son4ous [18]
The endpoints are the points which represent or marks the end of a line segment or an interval. So, the endpoints would be the same points given which are ( 5/3, 1 ) and ( 0, 2). The midpoint, on the other hand, is the point that is located halfway through the line segment or the interval. It divides the segment into two parts with equal lengths. We calculate it by the formula,
midpoint = ((x1 + x2) / 2, (y1 + y2) / 2)

We substitute the points given above to the formula as follows:


midpoint = ((5/3 + 0) / 2, (1 + 2) / 2)
midpoint = 5/6 , 3/2

So, the midpoint is located at point 5/6, 3/2.
5 0
3 years ago
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