Question

Find the volume of a square pyramid with base edges of 48 cm and a slant

Answer 1

The height of this pyramid will be:

√(26^2 - (48/2)^2) = 10cm

So the volume is: V = 1/3 * 48^2 * 10 = 7680 cm^3

Answer 2

Answer:- C) $7,680\ cm^3$

Explanation:-

Given: Base edge of square pyramid a= 48 cm

Slant height square pyramid l =26 cm

Let h be the height of the right pyramid

Thus,

$h^2=l^2-(\frac{a}{2})^2=26^2-(\frac{48}{2})^2=676-576=100\\\\\Rightarrow\ h=\sqrt{100}=10$

The volume of square pyramid$=\frac{1}{3}a^2h=\frac{1}{3}(48)^2(10)=7680\ cm^3$

Thus C is the right option.The volume of square pyramid= $7,680\ cm^3$