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Evgen [1.6K]
3 years ago
5

A boat travels 224 miles upstream in 8 hours. The next day it returns the same distance in 7 hours. Assuming the current remaine

d the same both ways, write and solve a system to determine the speed of the boat in still water and the currant of the stream.
Mathematics
1 answer:
amid [387]3 years ago
3 0

Answer:

Try dividing

Step-by-step explanation:

yes

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which pair of points forms line that does no intersect the line that passes through the points (5,7) and (7,7)?
Nuetrik [128]

Answer:

(8, -9), (11, -9)

Step-by-step explanation:

The points (5, 7) and (7, 7) are on a horizontal line in which the y-coordinates of all points are 7. The line has equation y = 7.

For a line to not intersect the line y = 7, it must be parallel to y = 7.

The answer is the pair of points which both have the same y-coordinate, and that y-coordinate is not 7.

From the choices you added to your comments, the only choice with two points with the same y-coordinate is (8, -9) and (11, -9). This is the answer.

Answer: (8, -9), (11, -9)

5 0
3 years ago
Read 2 more answers
If a ball is thrown into the air with a velocity of 34 ft/s, its height (in feet) after t seconds is given by y = 34t − 16t2. Fi
Finger [1]

<u>ANSWER: </u>

If a ball is thrown into the air with a velocity of 34 feet per second, then velocity of the ball after 1 second is 2 feet per second

<u>SOLUTION: </u>

Given, a ball is thrown into the air with a velocity of 34 feet per second

Initial velocity (u) = 34 feet per second

And also given a relation between displacement and time = \mathrm{y}=34 \mathrm{t}-16 \mathrm{t}^{2} --- eqn 1

We need to find the velocity when t = 1 ; v = ?

We know that, v = u + at and \mathrm{s}=\mathrm{ut}+\frac{1}{2} \mathrm{at}^{2}

where v is instantaneous velocity and u is initial velocity

a is acceleration

t is time interval  

s is displacement

using the displacement and time relation eqn (1) we get

Now, when t = 1, displacement s = 34(1) – 16(1)

\mathrm{ut}+\frac{1}{2} \mathrm{at}^{2}=34-16

34 \times 1+\frac{1}{2} \times a \times 1^{2}=18

34+\frac{a}{2}=18

\begin{array}{l}{\frac{a}{2}=18-34} \\\\ {\frac{a}{2}=-16} \\ {a=-16 \times 2} \\ {a=-32}\end{array}

here, -ve sign indicates that object is in deceleration . so acceleration is -32 ft/s

now put a value in v = u + at

v = 34 + (-32)(1)

v = 34 – 32

v = 2 ft/s

Hence, velocity of the ball after 1 second is 2 ft/s

6 0
3 years ago
2.8-4.4n-2n+7<br><br><br><br> QUICKLY BRAINLY IF CORRECT
Alenkasestr [34]

Step-by-step explanation:

=9.8-6.4n

just add them together as easy as that

7 0
3 years ago
Find the domain of the following relation. <br> R={(19,96),(20,101),(21,106),(22,111)}
mafiozo [28]
(x, y)

The domain are all the x-values, the range are all the y-values.

R={(19,96),(20,101),(21,106),(22,111)}

The domain is: 19, 20, 21, and 22
The range is: 96, 101, 106, and 111
7 0
3 years ago
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How many tenths are in 13.58
Naily [24]
Tenths is after the decimal so the tenths is 5.
3 0
3 years ago
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