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lisabon 2012 [21]
3 years ago
6

Ratio for the volumes of two similar pyramids, given that the ratio of their edge lengths is 8:3?

Mathematics
1 answer:
emmasim [6.3K]3 years ago
6 0
All you have to do is divide the left side of the ratio by 5 and the right side of the ratio by 7. The one that comes out even on both sides is the correct one.
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A 40 inch board is to be cut into three pieces so that the second price is 4times as long as the first piece and the third piece
Anastasy [175]

Answer:

Step-by-step explanation:

Givens

Let the first piece be x

Let the second piece 4x

Let the third piece = 5x

Total length = 40 inches.

Equation

x + 4x + 5x = 40                Combine

Solution

10x = 40                             Divide by 10

10x/10 = 40/10        

x = 4

Answer

The smallest piece (x) = 4

The middle piece 4x  = 4*4 = 16

The largest piece 5x= 5 * 4 = 20

3 0
1 year ago
HELP!!!!!
Sonja [21]
First off, let's convert the decimal to a fraction, notice, we have two decimals, so we'll use in the denominator, a 1 with two zeros then, two decimals, two zeros, thus   \bf 1.\underline{75}\implies \cfrac{175}{1\underline{00}}\implies \cfrac{7}{4}\implies \stackrel{ratio}{7:4}

now, we know then the ratio dimensions for the new photograph, 

\bf \qquad \qquad \textit{ratio relations}
\\\\
\begin{array}{ccccllll}
&\stackrel{ratio~of~the}{Sides}&\stackrel{ratio~of~the}{Areas}&\stackrel{ratio~of~the}{Volumes}\\
&-----&-----&-----\\
\cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3}
\end{array} \\\\
-----------------------------\\\\

\bf \cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s}{s}=\cfrac{\sqrt{s^2}}{\sqrt{s^2}}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\\\\
-------------------------------\\\\
\cfrac{7}{4}\implies \cfrac{4+3}{4}\implies \cfrac{4}{4}+\cfrac{3}{4}\implies 1+\boxed{\cfrac{3}{4}}\impliedby \textit{perimeter is }\frac{3}{4}\textit{ larger}
\\\\\\
\stackrel{areas'~ratio}{\cfrac{s^2}{s^2}}\implies \cfrac{3^2}{4^2}\implies \cfrac{9}{16}\impliedby \textit{area is }\frac{9}{16}\textit{ larger than original}
6 0
3 years ago
Need to know the area of the composite figure.
MariettaO [177]

Answer:

Step-by-step explanation:

you can figure out the area by using two formulas: area of a circle (on each end are two semi circles which when combined, make a circle) and area of a rectangle

Acircle: pi(r^2) = pi(5^2) = 25pi

Arectangle: length*width = 20*10 = 200ft^2

area of composite figure: (25pi ft^2) + 200ft^2

4 0
3 years ago
A driver intends to complete 2 laps on a track that is exactly 1 mile around at an average speed of 60 mph. He gets off to a slo
andrey2020 [161]

Answer:

Goal is not achievable

Step-by-step explanation:

There are Two laps and the total distance here is 2miles. Now, it is said that he hopes to travel at a speed of 60mph, thus the total time that it would take him to complete the 2 miles distance race is 2/60 = 1/30 hours. Thus if he travels at a constant speed of 60mph he would finish the race at 1/30hours.

This means he will take a time of 1/60 hours per lap.

Now, he travels 30mph to complete 1 mile, the time taken for this is 1/30h

We now need to know the speed he travels on the second lap.

Average speed = Total distance/Total time

60mph = 2/( 1/30 + T2)

60 = 2/( (1 + 30T2)/30)

60 = 2 divided by (1 + 30T2)/30

60 = 2 * (30)/1 + 30T2

60( 1 + 30T2) = 60

1 + 30T2 = 1

30T2 = 0

T2 = 0

This means that he cannot achieve his goal again as he had taken the time meant for the whole race in a single lap.

4 0
3 years ago
Only the function represented by graph has inverse function
KengaRu [80]

Answer:

rest of the question?

Step-by-step explanation:

3 0
3 years ago
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