If a= lw and if l= 1.5 and w = 0.75 what does a equal

Ship collisions in the Houston Ship Channel are rare. Suppose the number of collisions are Poisson distributed, with a mean of 1

alexandr1967 [171]

Answer:

$a) \simeq 0.3012$ $b) \simeq 0.0494$ c) $\simeq 0.2438$

Step-by-step explanation:

Rate of collision,

1.2 collisions every 4 months

or, $\frac{1.2}{4}$

= 0.3 collisions per month

So, the Poisson distribution for the random variable no. of collisions per month (X) is given by,

P(X =x) = $\frac{e^{-\lambda}\times {\lambda}^{x}}}{x!}
$

for x ∈ N ∪ {0}

= 0 otherwise --------------------------------------(1)

here, $\lambda = 0.3$ collision / month

No collision over a 4 month period means no collision per month or X =0

Putting X = 0 in (1) we get,

P(X = 0) = $\frac{e^{-0.3}\times {\0.3}^{0}}{0!}
$

$\simeq 0.7408182207$ ------------------------------------(2)

Now, since we are calculating this for 4 months,

so, P(No collision in 4 month period)

= $0.7408182207^{4}$

$\simeq 0.3012$ -----------------------------------------------------------(3)

2 collision in 2 month period means 1 collision per month or X =1

Putting X =1 in (1) we get,

P(X =1) = $\frac{e^{-0.3}\times {\0.3}^{1}}{1!}
$

$\simeq 0.2222454662$ ------------------------------------(4)

Now, since we are calculating this for 2 months, so ,

P(2 collisions in 2 month period)

= $0.2222454662^{2}$

$\simeq 0.0494$ -----------------------------------------(5)

1 collision in 6 months period means

$\frac{1}{6}$ collision per month

Now, P(1 collision in 6 months period)

= P( X = 1/6] (which is to be estimated)

= $\frac {P(X=0)\times 5 + P(X =1)\times 1}{6}$

= \frac {0.7408182207 \times 5 + 0.2222454662 \times 1}{6}[/tex]

$\simeq 0.6543894283$ -------------------------------------------(6)

So,

P(1 collision in 6 month period)

= $0.6543894283^{6}$

$\simeq 0.0785267444$ ------------------------------------------------(7)

So,

P(No collision in 6 months period)

= $(P(X =0)^{6}$

$\simeq 0.1652988882$ ---------------------------------(8)

so,

P(1 or fewer collision in 6 months period)

= (8) + (7 ) = 0.0785267444 +0.1652988882

$\simeq 0.2438$ ---------------------------------------------(9)

7 0

2 years ago

Prepare a perpetual inventory record, using the FIFO inventory costing method, and determine the company's cost of goods sol

krek1111 [17]

Answer:

The First-In, First-Out (FIFO) inventory costing method assumes that the inventory items ordered first are the first ones sold.

Step-by-step explanation:

The First-In, First-Out inventory costing method assumes that the inventory items ordered first are the first sold. This is ideal for goods that are highly perishable, for example fresh milk. Since no figures or dates are given, we will assume that the month is March 2019 and use any figures to make the example.

Date Item Quantity of stock Cost Price

01 Opening stock bought on Feb 28 10 100

05 Sale of 5 goods (cost is $10 each) (5) 50

15 Purchase of stock (20 goods at $20 each) 20 400

25 Sale of 15 goods (15) 250

(5 at $10 each & 10 at $20 each)

31 Closing Stock 10 200

(20 goods bought on 15th - 10 goods sold on 25th)

The quantity on hand at the end of the month is 10 units.

Total cost of goods on hand at end of the month = 10 units * $20 = 200.

Total cost of goods purchased during the month = $20 * 20 units = $400

Total cost of goods sold during the month = [($10 *5) + ($10 * 5)+ ($20 * 10)] = $200

6 0

3 years ago

Help Please! Find The Missing Sides Using Special Right Triangles.

matrenka [14]

Answer:

Choice 1

Step-by-step explanation:

m^2 +n^2=13^2

m^2=13^2-n^2

n^2=13^2-m^2

Both m & n =(13 x sq rt 2)/2

To put it another way:

m=(sq rt 2)/2 x 13

n=(sq rt 2)/2 x 13

6 0

2 years ago

What is the solution to the inequality shown? -2(x + 3) < 6 - x x > -12 x < -12 x > 12 x < 12

Sonja [21]

Answer:

x < -12

Step-by-step explanation:

Given the inequality

-2(x + 3) < 6 - x

Expand

-2x - 6 < 6 - x

Collect the like terms;

-2x + x < 6 + 6

-x < 12

Multiply through by -1

-1(-x) < -1(12)

x < -12

6 0

2 years ago

A theater technician charges a $200 flat fee and 5% of all profits from ticket sales per show. If the technician made $400 on a

RoseWind [281]

Answer:

$10

Step-by-step explanation:

$200 for the flat fee, then $400 X .05=$10

$10 is the amount made off of ticket sales.

7 0

3 years ago

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