Answer:
5:15
Step-by-step explanation:
The shorter "leg" show the hour and the longer "leg" shows the minutes. The minutes around the clock goes by 5s.
Answer:
x = -2, y=1
Step-by-step explanation:
x-7y=-9---------------------equation 1
-x+8y=10-------------------equation 2
From equation 1, make x the subject of formula
x=7y-9----------------------equation 3
substituting x=7y-9 in equation 2,
-(7y-9)+8y=10
Expanding bracket
-7y+9+8y=10
Collecting like terms
8y-7y=10-9
y=1
substituting y=1 in 3
x=7(1)-9
x=7-9
x=-2
Answer: y = -2/3(x-3)^2 + 0 or y = -2/3(x-3)^2
Step-by-step explanation:
vertex form is y=a(x-h)^2 + k
here we can see the vertex is (3,0) which is (x,y). Or (h,k) in this case.
so to plug that into vertex form, we now have y=a(x-3)^2 + 0. or just y=a(x-3)^2.
now we need to find "a" which is the leading coefficient. to do that we can plug in the (6,-6) for the x and y parts of the above equation. so we'd have
-6=a(6-3)^2. which goes to -6=a(2)^2 which is -6=4a. divide each side by 4 to get a = -2/3. plug this in for a
the final equation would be y = -2/3(x-3)^2 + 0 or y = -2/3(x-3)^2
Answer:
D.
Step-by-step explanation:
There is nothing in the figure to indicate the triangles are isosceles. This eliminates answer choices A, B, C.
Answer choice D is a required step in the proof, but only gets part of the way. The triangle similarity means ...
SQ/PQ = TQ/RQ
From here, you need to decompose each of the sides PQ and RQ into parts. Then you can get to the desired relationship.
(PQ -PS)/PQ = (RQ -RT)/RQ . . . segment sum theorem
1 - PS/PQ = 1 -RT/RQ . . . . . . . do the division
-PS/PQ = -RT/RQ . . . . . . . . subtract 1 (subtraction property of equality)
PS/PQ = RT/RQ . . . . . . . . multiply by -1 (multiplication property of equality)
