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timama [110]
3 years ago
7

An engineer needs to determine the amount of stone to order for a road construction project. The table shows the amount of stone

needed for each meter of highway, estimate the amount of each type of stone needed for a 290 meter section of the road, Estimate each value to the nearest 1000 tons.

Mathematics
2 answers:
Elis [28]3 years ago
8 0

Answer: 1013, 2962, and 7350

Step-by-step explanation:

you move the decimal point to the right until you get to the thousands place.

aliina [53]3 years ago
6 0
1013, 2962, and 7359
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Answer:

$34

Step-by-step explanation:

50% is half of 100%

(Because 50% x 2 = 100%)

Thus, half the money ($68) to find 50%.

So, 68÷2 = 34

Final answer is $34

Or

50/100 x $68 =$34

Hope this helps!

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What is the area of this face?​
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242 ft^2

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Vera ordered a soup, salad, and sandwich to share with her friends. The probabilities of each item being ready
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its

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3 years ago
Convert Зcis 180° to rectangular form.<br> А. -3<br> в. -3i<br> с. з<br> D. Зі.
Sunny_sXe [5.5K]

Answer:

-3

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3 cis(180^\circ) means 3(\cos(180^\circ)+i \sin(180^\circ))

What is the x-coordinate value that corresponds to \theta=180^\circ. That value is -1.

What is the y-coordinate value that corresponds to \theta=180^\circ. That value is 0.

So this implies \cos(180^\circ)=-1 \text{ and } \sin(180^\circ)=0.

3 cis(180^\circ)  

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5 0
3 years ago
Ann is adding water to a swimming pool at a constant rate. The table below shows the amount of water in the pool after different
N76 [4]

Answer:

(a)  As time increases, the amount of water in the pool increases.

     11 gallons per minute

(b)  65 gallons

Step-by-step explanation:

From inspection of the table, we can see that <u>as time increases, the amount of water in the pool increases</u>.

We are told that Ann adds water at a constant rate.  Therefore, this can be modeled as a linear function.  

The rate at which the water is increasing is the <em>rate of change</em> (which is also the <em>slope </em>of a linear function).

Choose 2 ordered pairs from the table:

\textsf{let}\:(x_1,y_1)=(8, 153)

\textsf{let}\:(x_2,y_2)=(12,197)

Input these into the slope formula:

\textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{197-153}{12-8}=\dfrac{44}{4}=11

Therefore, the rate at which the water in the pool is increasing is:

<u>11 gallons per minute</u>

To find the amount of water that was already in the pool when Ann started adding water, we need to create a linear equation using the found slope and one of the ordered pairs with the point-slope formula:

y-y_1=m(x-x_1)

\implies y-153=11(x-8)

\implies y-153=11x-88

\implies y=11x-88+153

\implies y=11x+65

When Ann had added no water, x = 0.  Therefore,

y=11(0)+65

y=65

So there was <u>65 gallons</u> of water in the pool before Ann starting adding water.

3 0
2 years ago
Read 2 more answers
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