f(x) = 6x
To find the inverse, replace f(x) with Y:
y = 6x
Now switch the variables:
x = 6y
Solve for Y by dividing both sides by 6:
y = x/6
Now replace y with f^-1 (x):
f^-1 (x) = x/6
Answer:
(x, y) = (5, 1)
Step-by-step explanation:
To <em>eliminate</em> x, you can double the second equation and subtract the first.
... 2(x +4y) -(2x -3y) = 2(9) -(7)
...11y = 11 . . . . . simplify
... y = 1 . . . . . . divide by 11
Using the second equation to find x, we have ...
... x + 4·1 = 9
... x = 5 . . . . . subtract 4
_____
<u>Check</u>
2·5 -3·1 = 10 -3 = 7 . . . . agrees with the first equation
(Since we used the second equation to find x, we know it will check.)
Answer:
I can see any expressions
4x - 5y = -15
y = -3x + 22
Plug in your y= equation into the y variable in the other equation
4x - 5 (y) = -15
^^
y = (-3x + 22) = -15
4x - 5 (-3x + 22) = -15
Distribute
4x + 15x - 110 = -15
Combine like terms and add 110 over to -15
19x = 95
Then, divide the whole equation by 19
x = 5
Then, plug in your x into your y= equation
y = -3 (5) + 22
y = -15 + 22
y = 7
<em><u>x = 5</u></em>
<em><u>y = 7</u></em>
<em><u>(5, 7)</u></em>
The volume of one cone would be 29 in³.
The formula for the volume of a cone is V=(1/3)πr²h. Substituting our information we have:
V=(1/3)(3.14)(4/2)²(7)
We divide the diameter by 2 because the radius is half of the diameter. This gives us:
V=1/3(3.14)(28) = 29.306 ≈ 29in³
