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N76 [4]
2 years ago
11

Which equation represents the function? f(x)=−1/2x+4 f begin argument x end argument equals negative fraction 1 over 2 end fract

ion x plus 4 f(x)=2x+12 f begin argument x end argument equals 2 x plus 1 half f(x)=4x−2 f begin argument x end argument equals 4 x minus 2 f(x)=−2x+4
Mathematics
1 answer:
PolarNik [594]2 years ago
4 0

The equation that represents the function is y = -x - 1

<h3>How to determine the equation of the function?</h3>

The complete question is added as an attachment

From the table of values, we have the following points

(x, y) = (-1,0) and (0,-1)

Calculate the slope (m) using

m = (y2 - y1)/(x2 - x1)

Substitute the known values in the above equation

m = (-1 -0)/(0 + 1)

Evaluate the exponent

m = -1

The equation is then calculated as:

y = mx + c

This gives

y = -x + c

Using the point (0,-1), we have:

0 = 1 + c

Solve for c

c = -1

So, we have

y = -x - 1

Hence, the equation that represents the function is y = -x - 1

Read more about linear functions at:

brainly.com/question/1884491

#SPJ1

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7 0
3 years ago
Read 2 more answers
A container holds 9 red markers, 13 blue markers, and 17 green markers. You will randomly select two markers without replacement
IRISSAK [1]

Answer:

a.

                         R-------8/38--------RR

R------9/39--------B-------13/38-------RB

                          G------17/38--------RG

                          R-------9/38--------BR

B--------13/39------B-------12/38-------BB

                           G-------17/38-------BG

                             R-----9/38--------GR

G---------17/39-------B------13/38-------GB

                              G------16/38-------GG

b).

  • 9 ways
  • ways you can select 1 blue are; RB,BR,BG,GB

RB=9/39 × 13/38=3/38

BR= 13/39 × 9/38 =3/38

BG= 13/39 × 17/38=17/114

GB= 17/39 × 13/38=17/114

=3/38 +3/38+17/114+ 17/114 =26/57

  • Probability of selecting 2 red markers= RR = 9/39 × 8/38 =12/247

  • Probability of selecting a green marker and then a red marker= GR= 17/39×9/38 =51/494

8 0
3 years ago
A hot-air balloon at 1020 feet descends at a rate of 85 feet per minute. Let y represent the height of the balloon and let x rep
Lady_Fox [76]
Y=1020-85x because since it's a decrease it would be goung do, hence the subtraction
8 0
3 years ago
A container holds 5L of fluid. Does it hold more than or less than 500mL of fluid
Yuri [45]

There are 1000 mL in one liter, so there are 5000 Ml in the 5 L container. thus, it holds more than the 500 mL container. 
7 0
3 years ago
1. (5pts) Find the derivatives of the function using the definition of derivative.
andreyandreev [35.5K]

2.8.1

f(x) = \dfrac4{\sqrt{3-x}}

By definition of the derivative,

f'(x) = \displaystyle \lim_{h\to0} \frac{f(x+h)-f(x)}{h}

We have

f(x+h) = \dfrac4{\sqrt{3-(x+h)}}

and

f(x+h)-f(x) = \dfrac4{\sqrt{3-(x+h)}} - \dfrac4{\sqrt{3-x}}

Combine these fractions into one with a common denominator:

f(x+h)-f(x) = \dfrac{4\sqrt{3-x} - 4\sqrt{3-(x+h)}}{\sqrt{3-x}\sqrt{3-(x+h)}}

Rationalize the numerator by multiplying uniformly by the conjugate of the numerator, and simplify the result:

f(x+h) - f(x) = \dfrac{\left(4\sqrt{3-x} - 4\sqrt{3-(x+h)}\right)\left(4\sqrt{3-x} + 4\sqrt{3-(x+h)}\right)}{\sqrt{3-x}\sqrt{3-(x+h)}\left(4\sqrt{3-x} + 4\sqrt{3-(x+h)}\right)} \\\\ f(x+h) - f(x) = \dfrac{\left(4\sqrt{3-x}\right)^2 - \left(4\sqrt{3-(x+h)}\right)^2}{\sqrt{3-x}\sqrt{3-(x+h)}\left(4\sqrt{3-x} + 4\sqrt{3-(x+h)}\right)} \\\\ f(x+h) - f(x) = \dfrac{16(3-x) - 16(3-(x+h))}{\sqrt{3-x}\sqrt{3-(x+h)}\left(4\sqrt{3-x} + 4\sqrt{3-(x+h)}\right)} \\\\ f(x+h) - f(x) = \dfrac{16h}{\sqrt{3-x}\sqrt{3-(x+h)}\left(4\sqrt{3-x} + 4\sqrt{3-(x+h)}\right)}

Now divide this by <em>h</em> and take the limit as <em>h</em> approaches 0 :

\dfrac{f(x+h)-f(x)}h = \dfrac{16}{\sqrt{3-x}\sqrt{3-(x+h)}\left(4\sqrt{3-x} + 4\sqrt{3-(x+h)}\right)} \\\\ \displaystyle \lim_{h\to0}\frac{f(x+h)-f(x)}h = \dfrac{16}{\sqrt{3-x}\sqrt{3-x}\left(4\sqrt{3-x} + 4\sqrt{3-x}\right)} \\\\ \implies f'(x) = \dfrac{16}{4\left(\sqrt{3-x}\right)^3} = \boxed{\dfrac4{(3-x)^{3/2}}}

3.1.1.

f(x) = 4x^5 - \dfrac1{4x^2} + \sqrt[3]{x} - \pi^2 + 10e^3

Differentiate one term at a time:

• power rule

\left(4x^5\right)' = 4\left(x^5\right)' = 4\cdot5x^4 = 20x^4

\left(\dfrac1{4x^2}\right)' = \dfrac14\left(x^{-2}\right)' = \dfrac14\cdot-2x^{-3} = -\dfrac1{2x^3}

\left(\sqrt[3]{x}\right)' = \left(x^{1/3}\right)' = \dfrac13 x^{-2/3} = \dfrac1{3x^{2/3}}

The last two terms are constant, so their derivatives are both zero.

So you end up with

f'(x) = \boxed{20x^4 + \dfrac1{2x^3} + \dfrac1{3x^{2/3}}}

8 0
2 years ago
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