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erastova [34]
2 years ago
5

Find value of x 4(x+6)° (5x+11)°

Mathematics
1 answer:
Evgesh-ka [11]2 years ago
5 0

Value of x = 13°

Hope it helps you...

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Sung is going to rent a truck for one day. There are two companies he can choose from, and they have the following prices.
Alexus [3.1K]

Answer:

Step-by-step explanation:

Use the equation

89 < 75 + 0.7*M                Subtract 75 from both sides

89 - 75 < 0.7M                  Combine

14 < 0.7 M                          Divide both sides by 0.7

14/0.7 < M

20 < M

If M goes over 20 then the flat rate is cheaper.

8 0
2 years ago
.21 of what number is 7.98
AlladinOne [14]
.21 as a percentage is 21%
You can divide 7.98 by 21 then multiply by 100 which gives you an answer of 38.

Hope this helps :)
8 0
3 years ago
The pipe is leaking at 1.5 cups per day about how many gallons per week is the population
Inessa [10]
The question asks per week. So 1.5 cups times 7 days is 10.5 cups. 

The pipe leaks 10.5 cups every week.
6 0
3 years ago
A small business owner estimates his mean daily profit as $970 with a standard deviation of $129. His shop is open 102 days a ye
Katena32 [7]

Answer:

The probability that the shopkeeper's annual profit will not exceed $100,000 is 0.2090.

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean <em>μ</em> and standard deviation <em>σ</em> and we select appropriately huge random samples (<em>n</em> ≥ 30) from the population with replacement, then the distribution of the sum of values of <em>X</em>, i.e ∑<em>X</em>, will be approximately normally distributed.  

Then, the mean of the distribution of the sum of values of X is given by,  

 \mu_{x}=n\mu

And the standard deviation of the distribution of the sum of values of X is given by,  

 \sigma_{x}=\sqrt{n}\sigma

The information provided is:

<em>μ</em> = $970

<em>σ</em> = $129

<em>n</em> = 102

Since the sample size is quite large, i.e. <em>n</em> = 102 > 30, the Central Limit Theorem can be used to approximate the distribution of the shopkeeper's annual profit.

Then,

\sum X\sim N(\mu_{x}=98940,\ \sigma_{x}=1302.84)

Compute the probability that the shopkeeper's annual profit will not exceed $100,000 as follows:

P (\sum X \leq  100,000) =P(\frac{\sum X-\mu_{x}}{\sigma_{x}}

                              =P(Z

*Use a <em>z</em>-table for the probability.

Thus, the probability that the shopkeeper's annual profit will not exceed $100,000 is 0.2090.

6 0
3 years ago
a box is 24cm by 15cm by 10cm. this box will packed with smaller boxes of paper clips which are 6cm by 3cm by 5cm . what is the
vichka [17]

Answer: 40

Align in this pattern:

Bigger box : 24 : 15 : 10

smaller box: 6 : 3 : 5

counts: 4: 5 : 2

( multiply 4*5*2 = 40)

7 0
3 years ago
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