We know that
At sea level, the height is 0 and
the pressure is 98 kilopascals
At 1000 ft, the height is 1000 and
the pressure <span>decreases about 11.41%
</span>i(100%-11.41%)/100----> (0.8859)
therefore
1) at 1000 ft--------> the pressure is 98*(0.8859)----------> 86.82 kilopascals
2) at 2000 ft--------> the pressure is 86.82*(0.8859)-------> 76.91 kilopascals
3) at 3000 ft--------> the pressure is 76.91*(0.8859)-------> 68.14 kilopascals
4) at 4000 ft---------> the pressure is 68.14*(0.8859)-------> 60.36 kilopascals
the answer is
<span>The pressure at an altitude of 4000 m is about </span>60.36 kilopascals
The answer is 2/10
your just reducing the ratio
Answer:
Step-by-step explanation:
Solution :
hello :
note :
Use the point-slope formula.
y - y_1 = m(x - x_1) when : x_1= -1 y_1= 5
m= the slope is : (YC - YA)/(XC -XA)
(-1-2)/(0-3) = -3/-3 =1
( parallel to AC means same slope)
an equation in the point-slope form is : y -5 = 1(x+1)
y=x+6
Answer:
15
Step-by-step explanation:
6.14, and 9.21 are two decimals equivalent.