For #1. 3x + x +7 = 180 degrees
4x + 7 = 180
4x = 173
so x = 43.25
For #2. 2x + 5 = 110 degrees
2x = 105
so x = 52.5
For #3. 1 and 3, 2 and 4, 5 and 8, 6 and 7.
Answer:
50%
Step-by-step explanation:
Answer:
Problem 2: k = 3
Problem 4: NO SOLUTION
Step-by-step explanation:
Problem 2 work:
-4/3(12k + 27) = -57 - 9k
-16k - 36 = -57 - 9k -ADD THE -9k TO ITSELF AND TO -16k-
-7k - 36 = -57 -ADD THE -36 TO ITSELF AND -57-
-7k = -21
<u><em>k = 3</em></u>
<u><em /></u>
Problem 4 work:
5/2(6w - 16) = 18w -(3w + 40)
15w - 40 = 18w - 3w - 40 -ADD THE -3w TO THE 18w-
15w - 40 = 15w - 40
NO SOLUTION BECAUSE BOTH SIDES ARE THE SAME
3 is odd
So by the question he will lose 10 times the number that comes up
3*10=-30
The probability of winning exactly 21 times is 0.14 when the probability of winning the arcade game is 0.659.
We know that binomial probability is given by:
Probability (P) = ⁿCₓ (probability of 1st)ˣ x (1 - probability of 1st)ⁿ⁻ˣ
We are given that:
Probability of winning on an arcade game = P(A) = 0.659
So, the Probability of loosing on an arcade game will be = P'(A) = 1 - 0.659 = 0.341
Number of times the game is being played = 30
We have to find the Probability of winning exactly 21 times.
Here,
n = 30
x = 21
P(A) = 0.659
P'(A) = 0.341
Using the binomial probability formula, we get that:
Probability of winning exactly 21 times :
P(21 times) = ³⁰C₂₁ (0.659)²¹ x (0.341)⁷
P( 21 times ) = 0.14
Therefore, the probability of winning exactly 21 times is 0.14
Learn more about " Binomial Probability " here: brainly.com/question/12474772
#SPJ4
