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Hunter-Best [27]
3 years ago
9

This question confuses me help please. :(

Mathematics
1 answer:
Charra [1.4K]3 years ago
3 0

Hi!

First, find the total percent of vehicles with at least 3 people.

15% + 7% + 3% = 25%

Now find 25% of 420

Set up a proportion and cross multiply to solve.

\frac{x}{420} \frac{25}{100}

25 * 420 = 10500

10500/100 = 105

The answer is 105 vehicles contained at least 3 people.

Hope this helped! :)

-Peredhel

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Volgvan

Hello,

x² + 5x + 6 = 0

a = 1 ; b = 5 ; c = 6

∆ = b² - 4ac = 5² - 4 × 1 × 6 = 25 - 24 = 1 > 0

2 solutions :

x_{1} =  \frac{ - b -  \sqrt{\Delta} }{2a}  =  \frac{ - 5 - 1}{2 \times 1}  =  \frac{ - 6}{2}  =  - 3

x_{2} =  \frac{ - b  +   \sqrt{\Delta} }{2a}  =  \frac{ - 5  + 1}{2 \times 1}  =  \frac{ - 4}{2}  =  - 2

S = { -3 ; -2}

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Suppose C and D represent two different school populations where C &gt; D and C and D must be greater than 0. Whitch of the foll
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<em>A. (C+D)^2  is the largest expression</em>

Step-by-step explanation:

<u>Squaring Properties </u>

The square of a number N is shown as N^2 and is the product of N by itself, i.e.  

N^2=N*N

If N is positive and less than one, its square is less than N, i.e.

N^2

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We have the following information: C and D represent two different school populations, C > D, and C and D must be positive. We can safely assume C and D are also greater or equal than 1. Let's evaluate the following expressions to find out which is the largest

A. (C+D)^2

Expanding  

(C+D)^2=C^2+2CD+D^2

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B. 2(C+D)

The extreme case is when C=2 and D=1 (recall C>D). It results:

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The expression can be written as

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Comparing with A.

(C+D)^2=(C+D)(C+D)

The subtracting factor (C-D) makes this product smaller than A which has two adding factors.

Thus A. is the largest expression

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