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Vedmedyk [2.9K]
3 years ago
10

1/6 + 3/8 A. 4/6 B. 4/8 C. 4/14 D. 13/24

Mathematics
1 answer:
Naddika [18.5K]3 years ago
8 0

Here is you're answer:

In order to get you're answer you need to find the common denominator then add.

  • \frac{1}{6} + \frac{3}{8}
  • Find the common denominator:
  • CD = 48
  • = \frac{26}{48}
  • Simplify:
  • \frac{26}{48} \div 2 = \frac{13}{24}
  • = \frac{13}{24}

Therefore you're answer is option D "13/24."

Hope this helps!

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A wise man once said “400 reduced by 3 times my age is 244.” How old is the wise man?
Readme [11.4K]

Answer:

52 years old

Step-by-step explanation:

let this mans age be a

400-3a=244

400=244+3a

400-244=3a

156=3a

a=52

7 0
3 years ago
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Simplify the numerical expression: -4.2 + 8.1 x ( -1.9)
SIZIF [17.4K]
-19.59 is your answer because u do PEMDAS and that would be 8.1*(-1.9) which gives you -15.39 Then you do -4.2+-15.39 and you would get -19.59
3 0
3 years ago
Juanita gets paid for every apron she embroiders. Last week she earned $185. If she earns $2.50 for each embroidered piece, how
GenaCL600 [577]

Answer:74

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
What is the length of AC?
Alenkasestr [34]
So in order to find line AC you must find line AD and DC then plus them together.

to find AD use Pythagoras theorem
a^2 = c^2 - b^2
AD^2 = 7.5^2 - 6.5^2
AD^2 = 56.25 - 42.25
AD^2 = 14
square root both sides to get rid of the ^2
AD ≈ 3.7 or 3.74

Do the same for DC
DC^2 = 10^2 - 6.5^2
DC^2 = 100 - 42.25
DC^2 = 57.75
DC ≈ 7.6

now plus AD and DC which should give u 11.3
5 0
3 years ago
(I've been trying to figure this out for 3 days and I really need help)
liq [111]

Check the picture below.

since the diameter of the cone is 6", then its radius is half that or 3", so getting the volume of only the cone, not the top.

1)

\bf \textit{volume of a cone}\\\\ V=\cfrac{\pi r^2 h}{3}~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=3\\ h=4 \end{cases}\implies V=\cfrac{\pi (3)^2(4)}{3}\implies V=12\pi \implies V\approx 37.7

2)

now, the top of it, as you notice in the picture, is a semicircle, whose radius is the same as the cone's, 3.

\bf \textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=3 \end{cases}\implies V=\cfrac{4\pi (3)^3}{3}\implies V=36\pi \\\\\\ \stackrel{\textit{half of that for a semisphere}}{V=18\pi }\implies V\approx 56.55

3)

well, you'll be serving the cone and top combined, 12π + 18π = 30π or about 94.25 in³.

4)

pretty much the same thing, we get the volume of the cone and its top, add them up.

\bf \stackrel{\textit{cone's volume}}{\cfrac{\pi (3)^2(8)}{3}}~~~~+~~~~\stackrel{\stackrel{\textit{half a sphere}}{\textit{top's volume}}}{\cfrac{4\pi 3^3}{3}\div 2}\implies 24\pi +18\pi \implies 42\pi ~~\approx~~131.95~in^

8 0
3 years ago
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