Let g and b represent the numbers of grandstand and bleacher tickets sold.
.. g + b = 5716 . . . . . . . . . total number of tickets sold
.. 65g +40b = 341690 . . value of tickets sold
Using the first equation
.. g = 5716 -b
Sustituting into the second equation
.. 65(5716 -b) +40b = 341690
.. -25b + 371540 = 341690 . . . . . collect terms
.. -25b = -29850 . . . . . . . . . . . . . . subtract 371540
.. b = 1194 . . . . . . . . . . . . . . . . . . . . divide by -25
1194 bleacher tickets were sold.
The minimum value is the lowest point of a graphed line. The would be the bottom of the "U" shape.
Looking at the graph you can see that the bottom of the U is touching the horizontal line at x = -5.5, so this would be the minimum value.
The lowest part of the line is at -5.5
The correct question is:
Suppose x = c1e^(-t) + c2e^(3t) a solution to x''- 2x - 3x = 0 by substituting it into the differential equation. (Enter the terms in the order given. Enter c1 as c1 and c2 as c2.)
Answer:
x = c1e^(-t) + c2e^(3t)
is a solution to the differential equation
x''- 2x' - 3x = 0
Step-by-step explanation:
We need to verify that
x = c1e^(-t) + c2e^(3t)
is a solution to the differential equation
x''- 2x' - 3x = 0
We differentiate
x = c1e^(-t) + c2e^(3t)
twice in succession, and substitute the values of x, x', and x'' into the differential equation
x''- 2x' - 3x = 0
and see if it is satisfied.
Let us do that.
x = c1e^(-t) + c2e^(3t)
x' = -c1e^(-t) + 3c2e^(3t)
x'' = c1e^(-t) + 9c2e^(3t)
Now,
x''- 2x' - 3x = [c1e^(-t) + 9c2e^(3t)] - 2[-c1e^(-t) + 3c2e^(3t)] - 3[c1e^(-t) + c2e^(3t)]
= (1 + 2 - 3)c1e^(-t) + (9 - 6 - 3)c2e^(3t)
= 0
Therefore, the differential equation is satisfied, and hence, x is a solution.
Answer:
Use this formula for these kinda things.
Step-by-step explanation:
Remember The z is the hypathonous, it means the biggest side.
where Z is going to be C
put this all together
put it into calculator, means 373=
therfore take the square root, it will be
which it will be 19.31
