Question

Three different sets of objects contain 4, 5, and 12 objects, respectively. How

Answer 1

Answer:

$\text{B. }240}$

Step-by-step explanation:

$\binom{4}{1}\cdot\binom{5}{1}\cdot \binom{12}{1}=\boxed{\text{B. }240}}$

(Multiplying each of the numbers also yields 240)