Both mean and median are measures of the center of a set of data.
Mean is normally preffered to the median except if there is an outlier that has a tendency to affect the mean.
An outlier is a data point that significantly differs from the other data points in a sample.
In the data set above, there is no outlier that will affect the mean.
Therefore, he should use the mean because there are no outliers that affect the mean.
        
                    
             
        
        
        
Answer:
Step-by-step explanation:
TYSM
HAVE A GREAT DAY
 
        
             
        
        
        
9514 1404 393
Answer:
  2 nickels, 9 dimes
Step-by-step explanation:
When there are a number of overlapping shaded areas on the graph, I find it convenient to use the reverse of the inequalities. That makes the <em>unshaded</em> area the solution space. Here, the vertices of the triangular solution space are ...
   (2, 9), (2, 13), (6, 9)
Any of the grid points within (or on) this triangle is a possible solution. One of them is (2, 9) corresponding to 2 nickels and 9 dimes.
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Three solutions are shown:
   (x, y) = (2, 9), (3, 10), (4, 11)