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kozerog [31]
3 years ago
11

Which r–value represents the strongest negative correlation? –0.7 –0.22 0.38 0.9

Mathematics
2 answers:
Agata [3.3K]3 years ago
7 0

Answer:

-.7

Step-by-step explanation:

A

inn [45]3 years ago
3 0

Answer:

Option A is correct.

The value of r = -0.7 represents the strongest negative correlation.

Step-by-step explanation:

A correlation is a  value that describes a relationship between two things  or variables.

Strongest Negative Correlation says that closer a negative correlation to -1, the stronger the relationship between the two variables.

From the options,  we have only two negative values i.e, r= -0.7 and r= -0.22.

We have to find the strongest negative correlation r-value.

By the definition, you can see that -0.7 is very closer to -1 ,

therefore, the  value of r = -0.7 represents the strongest negative correlation.


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Answer:  The calculations are done below.


Step-by-step explanation:

(i) Let the vertices be A(2,0), B(3,2) and C(5,1). Then,

AB=\sqrt{(2-3)^2+(0-2)^2}=\sqrt{5},\\\\BC=\sqrt{(3-5)^2+(2-1)^2}=\sqrt{5},\\\\CA=\sqrt{(5-2)^2+(1-0)^2}=\sqrt{10}.

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AB=\sqrt{(4-6)^2+(2-2)^2}=\sqrt{4}=2,\\\\BC=\sqrt{(6-5)^2+(2-3.73)^2}=\sqrt{14.3729},\\\\CA=\sqrt{(5-4)^2+(3.73-2)^2}=\sqrt{14.3729}.

Since, BC = CA, so the triangle ABC will be an isosceles triangle.

(iii) Let the vertices be A(-5,2), B(-4,4) and C(-2,2). Then,

AB=\sqrt{(-5+4)^2+(2-4)^2}=\sqrt{5},\\\\BC=\sqrt{(-4+2)^2+(4-2)^2}=\sqrt{8},\\\\CA=\sqrt{(-2+5)^2+(2-2)^2}=\sqrt{9}.

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AB=\sqrt{(-3+3)^2+(1-4)^2}=\sqrt{9}=3,\\\\BC=\sqrt{(-3+1)^2+(4-1)^2}=\sqrt{13},\\\\CA=\sqrt{(-1+3)^2+(1-1)^2}=\sqrt 4.

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AB=\sqrt{(-4+2)^2+(2-4)^2}=\sqrt{8},\\\\BC=\sqrt{(-2+1)^2+(4-4)^2}=\sqrt{1}=1,\\\\CA=\sqrt{(-1+4)^2+(4-2)^2}=\sqrt{13}.

Since AB ≠ BC ≠ CA, and so this will be an obtuse scalene triangle, because one angle that is opposite to CA will be obtuse.

Thus, the match is done.

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