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Svetradugi [14.3K]
3 years ago
6

Given the domain {-2, 1, 5}, what is the range for the relation 4x + y = 3?

Mathematics
1 answer:
dybincka [34]3 years ago
4 0

Answer:

Its the first one

Step-by-step explanation:

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Mr. smith has 5 courses he teaches at the community college. his course a has 102 students with an average tardiness of 3 studen
Furkat [3]

The percentage of tardiness among the 102 pupils is 2.94.

<h2>Calculation of the percentage</h2>

According to the query,

Course A: Total number of students = 102

                   Number of tardy students = 3

Percent of students tardy in course A = (number of tardy students/total  

                                                                   number of students) * 100

  =(3/102)*100

  = 2.941

  ≈2.94

In case of course B: Total number of students = 85 & tardy student = 5

So, the percent of tardy student = (5/85)*100 = 5.88 %

Therefore, it is concluded that the percentage of student tardiness in course A is 2.94.

Learn more about the percentage here:

brainly.com/question/92258

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5 0
2 years ago
PLS HELP ASAP! GIVING BRAINLY
ioda
The answer would be (x+1) and (x+10) so E
4 0
2 years ago
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Calculate the area of triangle that has height of 4 and one side is 3 ?
jolli1 [7]
Take 0.5x4x3=6 So the answer is 6.
7 0
3 years ago
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Solve for angle C.<br><br><br><br><br> •
blagie [28]

Answer: 40º

Step-by-step explanation:

To find angle c, not give 2 angles at least, we must use a trigonometric function. With respect to angle c, we can see that we have the opposite and adjacent sides.

The trigonometric function that relates opposite and adjacent sides is tangent.

tan=\frac{opposite}{adjacent}

tan=\frac{21}{25}

tan^-^1=40

8 0
3 years ago
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Is 11/128 equal to a terminating decimal or a repeating decimal ? Explain how you know
Ostrovityanka [42]

We need to determine whether \frac{11}{128} is a terminating decimal or a repeating decimal.

Let's solve this question using the long division method

First, let's identify the divisor and dividend. The number to be divided is 11 hence this is the dividend, and it needs to be divided by 128 which is the divisor

Next, since the divisor (128) is greater than the dividend (11) it can not divide 11. Hence, we will introduce a decimal point in quotient, and append a 0 next to 11 and divide 110 by 128. Again, 128 is greater than 110 so we will introduce a 0 in the quotient, and append another 0 next to 110, and will divide 1100 by 128. We will see what multiple of 128 is less than or equal to 1100. That multiple is 8. So we write 8 in the quotient and multiply 128 with 8 and subtract the product (128*8 = 1024) from 1100. The remainder that we get is 76.

Next, we append a 0 to the remainder and divide 760 by 128. Now, we see what multiple of 128 is less than or equal to 760. That multiple is 5. So we write 5 next to the quotient and multiply 128 with 5 and subtract the product (640) from 760. Now, the remainder is 120.

Next, we append a 0 to the remainder and divide 1200 by 128. Now, we see what multiple of 128 is less than or equal to 1200. That multiple is 9. So we write 9 next to the quotient and multiply 128 with 9 and subtract the product (1152) from 1200. Now, the remainder is 48.

Next, we append a 0 to the remainder and divide 480 by 128. Now, we see what multiple of 128 is less than or equal to 480. That multiple is 3. So we write 3 next to the quotient and multiply 128 with 3 and subtract the product (384) from 480. Now, the remainder is 96.

Next, we append a 0 to the remainder and divide 960 by 128. Now, we see what multiple of 128 is less than or equal to 960. That multiple is 7. So we write 7 next to the quotient and multiply 128 with 7 and subtract the product (896) from 960. Now, the remainder is 64.

Next, we append a 0 to the remainder and divide 640 by 128. Now, we see what multiple of 128 is less than or equal to 640. That multiple is 5. So we write 5 next to the quotient and multiply 128 with 5 and subtract the product (640) from 640. Now, the remainder is 0.

Hence, we have solved the entire problem

Last, we look at the quotient i.e. 0.0859375, which is the solution to the problem. We see that the quotient has a definite number of digits in it, and terminates at 5. Hence, this is a terminating decimal.

A repeating decimal is one in which a particular pattern after the decimal point keeps re-occuring, which is not the case here. Hence, \frac{11}{128} is a terminating decimal.

Please refer to the attached image for visualization

3 0
3 years ago
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