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3 years ago

Please help me! Thanks in advance...

Mathematics

1 answer:

adell [148]3 years ago

3 0

Density of water won't change.

and u should not keep it on the table as it cant support its weight which is

w= density*volume = 62*(3*3*3) =1674 lb which is way greater than 200 lb

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Which two words can describe the same shape

belka [17]

Answer:

square, anddddddddddddddddd deskkkkkk I thinkjkkkkk

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2 years ago

Find the sum of the first 8 terms of the sequence. <br><br> 1, -3, -7, -11, ...

Darya [45]

$1+(-3)+(-7)+(-11)+(-15)+(-19)+(-23)+(-27) = \\1-3-7-11-15-19-23-27 = \\-35-19-23-27= \\-35-19-50=\boxed{-104}$

Hope this helps.

r3t40

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3 years ago

Find the surface area <br><br> PlzzZz TIA

BARSIC [14]

Answer:

Step-by-step explanation:

because is going up and is increasing

6 0

2 years ago

A car is moving with a velocity (3.0 m/s) x̂ + (1.0 m/s) ŷ and 3.0 seconds later its velocity is (6.0 m/s) x̂ - (3.0 m/s) ŷ. Wha

Mars2501 [29]

Here we know that the initial velocity of the car is given by:

$V_i=(3.0\hat x+1.0\hat y)m/s$

And the final velocity of the car is given by:

$V_f=(6.0\hat x-3.0\hat y)m/s$

It took 3 seconds to attain the final velocity, so we have $t=3 s$

Therefore, the acceleration can be obtained by:

$V_f-V_i=a\times t$

$a=\frac{V_f-V_i}{t}$

Plugging the values of the initial, final velocity and the time, we get:

$a= \frac{(6\hat x-3\hat y)-(3 \hat x+1 \hat y)}{3} =\frac{6\hat x-3 \hat y -3 \hat x-1 \hat y}{3} =\frac{3 \hat x-4 \hat y}{3}$

So the acceleration of the car is given by:

$a=\frac{3 \hat x}{3} -\frac{4 \hat y}{3} =1 \hat x- \frac{4}{3} \hat y$

Now we need to find the direction of the average acceleration of the car:

$\theta=tan^{-1} \frac{y}{x}$

Here, x and y are the coefficients of the 'x' and 'y' components of the vector:

$\theta=tan^{-1}(\frac{-\frac{4}{3} }{1} )=tan^{-1}(\frac{-4}{3}) =-53.13^\circ$

Therefore, the direction of the average acceleration of the car is $-53.13^\circ$ .

8 0

3 years ago

Suppose a production line operates with a mean filling weight of 16 ounces per container. Since over- or under-filling can be da

miss Akunina [59]

Answer:

From the question we are told that

The population mean is $\mu = 16$

The sample size is n = 30

The sample mean is $\= x = 16.32$

The population standard deviation is $\sigma = 0.8$

The level of significance is $\alpha = 0.10$

Step 1: State hypotheses:

The null hypothesis is $H_o : \mu = 16$

The alternative hypothesis is $H_a : \mu \ne 16$

Step 2: State the test statistic. Since we know the population standard deviation and the sample is large our test statistics is

$t = \frac{ \= x -\mu }{ \frac{\sigma}{ \sqrt{n} } }$

=> $t = \frac{ 16.32 -16 }{ \frac{0.8 }{ \sqrt{30} } }$

=> $t =2.191$

Generally the degree of freedom is mathematically represented as

$df = n - 1$

=> $df = 30 - 1$

=> $df =29$

Step 3: State the critical region(s):

From the student t-distribution table the critical value corresponding to $\alpha = 0.10$ is

$t = 1.311$

Generally the critical regions is mathematically represented as

$- 1.311 < T < 1.311$

Step 4: Conduct the experiment/study:

Generally the from the value obtained we see that the t value is outside the critical region so the decision is [Reject the null hypothesis ]

Step 5: Reach conclusions and state in English:

There is sufficient evidence to show that the filling weight has to be adjusted

Step 6: Calculate the p-value associated with this test. How does this the p-value support your conclusions in Step 5?

From the student t-distribution table the probability value to the right corresponding to $t =2.191$ at a degree of freedom of $df =29$ is

$P( t > 2.191) = 0.0183$

Generally the p-value is mathematically represented as

$p-value = 2 * P( t > 2.191 )$

=> $p-value = 2 * 0.0183$

=> $p-value = 0.0366$

Generally looking at the value obtained we see that $p- value < \alpha$ hence

The decision rule is

Reject the null hypothesis

Step-by-step explanation:

4 0

3 years ago