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2 years ago

7

Which properties are used to simplify 4/5y+3(2/5x+7/5y) to 5y+6/5x

1 answer:

SSSSS [86.1K]2 years ago

8 0

4/5y + 3(2/5x + 7/5y)...distribute thru the parenthesis
4/5y + 6/5x + 21/5y ...combine like terms
25/5y + 6/5x.....reduce
5y + 6/5x

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1.15 cg = __ g . A. 0.0115. B. 0.115. C. 11.5. D. 115. i think either C or D.

snow_lady [41]

The item above may be answered by using the dimensional analysis and the conversion factors. 1 gram is equal to 100 centigram. From this,
(1.15 cg ) x (1 g / 100 cg) = 0.0115 g
Therefore, the answer is letter A. 0.0115.

5 0

2 years ago

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Use Euler's method with step size 0.2 to estimate y(1), where y(x) is the solution of the initial-value problem y' = x2y − 1 2 y

GuDViN [60]

Answer:

Euler's method is a numerical method used in calculus to approximate a particular solution of a differential equation. As a numerical method, we have to apply the same procedure many times, until get the desired result.

In first place, we need to know all the values the problem is giving:

The step size is 0.2; h = 0.2. This step size is a periodical increase of the x-variable, which will allow us to calculate each y-value to each x.
The problem is asking the solution y(1), which means that we have to find the y-value assigned for x = 1, through the numerical method.
The initial condition is y(0) = 9. In other words, $x_{o} = 0\\y_{0}=9$ .

So, if the initial x-value is 0, and the step size is 0.2, the following x-value would be: $x_{1}=0.2$ ; then $x_{2}=0.4$ ; $x_{3} =0.6; x_{4} =0.8;x_{5} =1$ ; and so on.

Now, we have to apply the formula to find each y-value until get the match of $x_{5}=1$ , because the problem asks the solution y(1).

According to the Euler's method:

$y_{1} =y_{0} +hF(x_{0};y_{0})\\y_{2} =y_{1} +hF(x_{1};y_{1})\\y_{n} =y_{n-1} +hF(x_{n-1};y_{n-1})$

Where $F(x;y)=x^{2} y-12y^{2}$ , and $x_{0} =0; y_{0} =9$ ; $h=0.2$ .

Replacing all values we calculate the y-value assigned to $x_{1}$ :

$y_{1} =9+0.2((0)^{2} 9-12(9)^{2})=-185.4$ .

Now, $y_{1} =-185.4$ , $x_{1} =0.2; h=0.2$ . We repeat the process with the new values:

$y_{2} =y_{1} +hF(x_{1};y_{1}) \\y_{2} = -185.4+0.2((0.2)^{2} (-185.4)-12(-185.4)^{2} )\\y_{2}=-82682.47$

Then, we repeat the same process until get the y-value for $x_{5} =1$ , which is $y_{5} = -1.0018$ , round to four decimal places.

Therefore, $y(1)=-1.0018$ .

7 0

3 years ago

What is the justification for step 1

solniwko [45]

Answer:

what are you talking about??????

6 0

2 years ago

The scale on the map is stated as 1 : 200000. A main road connects two towns which are 28 kilometres apart. How far will it be o

loris [4]

Answer:

The distance on the map between the two towns=14 cm

Step-by-step explanation:

Step 1

Express the scale as;

1:200,000 this means that 1 cm on the map represents 200,000 cm on the road, 1 cm:200,000 cm

Step 2

Convert 28 kilometers to m

1 meter=1,000 kilometers

28 kilometers=28×1,000=28,000 meters

Convert 28,000 meters to centimeters

1 meter=100 centimeters

28,000 meters=28,000×100=2,800,000 centimeters

Step 3

Using the scale factor of 1:200,000 convert 2,800,000 cm on the road can be converted to map measurements as follows;

Distance on the map=scale factor×distance on the road

where;

scale factor=1/200,000

distance on the road=2,800,000 cm

replacing;

Distance on the map=(1/200,000)×2,800,000

Distance on the map=14 cm

The distance on the map between the two towns=14 cm

5 0

3 years ago

7 less than 5 times f is 18

prisoha [69]

Answer:

2 1/5

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers