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posledela
2 years ago
14

Jack is in a helicopter and looking down at two friends’ homes. The angle of depression to the first home is 72°. The angle of d

epression to the second home is 49°. If the homes are 420m apart, what is the distance between the helicopter and the first home?
Mathematics
1 answer:
alexandr402 [8]2 years ago
5 0

The distance between the helicopter and the first home is 369. 87 m

<h3>How to solve the distance using the angle of depression?</h3>

The distance between the helicopter and the first home can be found using sine law,

Hence,

180 - 72 - 49 = 59 degrees.

Therefore,

420 / sin 59 = A / sin 49°

where

  • A  = distance form the first home to the helicopter.

cross multiply

420 sin 49 = A sin 59°

A = 420 sin 49 / sin 59

A = 316.978023694 / 0.8571673007

A = 369.869339199

A = 369. 87 m

Therefore, the distance between the helicopter and the first home is 369. 87 m

learn more on angle of depression here: brainly.com/question/1976859

#SPJ1

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Read 2 more answers
Please help answer !!
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Answer:

32.3

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First we want to make a triangle like on the left side, so make a new point on AD that is directly below C, we'll call this E.

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now we want to find the last leg of this new triangle CED, the non hypotenuse.  We know AD is 24 CM.  It is now sebarated into three parts, the beginning part in the left most triangle, the 10 cm between the triangles and the side we want to find.  Since we know the middle part  we want to find the left part.


The left part of AD can be found with the pythagorean theorem.  7.5^2=6^2+x^2 this can be turned into \sqrt{7.5^2+6^2}=x=4.5  Now we know 24 = 10 + 4.5 + y, with y being the right part.  So now we know y=9.5


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