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3 years ago

4x²-17x-42 by factor

1 answer:

5 0

4x²-17x-42
=4(x²-17/4x)-42
=4[x²-17/4 x+(-17/8)²-(-17/8)²]-42
=4(x-17/8)²-289/64-42
=4(x-17/8)²-(289+2688)/64
=4(x-17/8)²-2974/64
=[(2x-34/8)²-(√2974/8)²]
=(2x-34/8 +(√2974/8))(2x-34/8-(√2974/8)
=[2x+(√2974-34)/8][2x-(√2974+34)/8]

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Damm [24]

Answer:

The margin of error for this estimate is of 14.79 yards per game.

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

T interval

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 20 - 1 = 19

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 19 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.95}{2} = 0.975$ . So we have T = 2.093

The margin of error is:

$M = T\frac{s}{\sqrt{n}}$

In which s is the standard deviation of the sample and n is the size of the sample.

You randomly select 20 games and see that the average yards per game is 273.7 with a standard deviation of 31.64 yards.

This means that $n = 20, s = 31.61$

What is the margin of error for this estimate?

$M = T\frac{s}{\sqrt{n}}$

$M = 2.093\frac{31.61}{\sqrt{20}}$

$M = 14.79$

The margin of error for this estimate is of 14.79 yards per game.

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2 years ago

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saveliy_v [14]

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Read 2 more answers

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2 years ago