1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
yan [13]
3 years ago
15

4x²-17x-42 by factor

Mathematics
1 answer:
kkurt [141]3 years ago
5 0
4x²-17x-42
=4(x²-17/4x)-42
=4[x²-17/4  x+(-17/8)²-(-17/8)²]-42
=4(x-17/8)²-289/64-42
=4(x-17/8)²-(289+2688)/64
=4(x-17/8)²-2974/64
=[(2x-34/8)²-(√2974/8)²]
=(2x-34/8  +(√2974/8))(2x-34/8-(√2974/8)
=[2x+(√2974-34)/8][2x-(√2974+34)/8]

You might be interested in
A rental car company charges $80 per day to rent a car and $0.10 for every mile driven. Alyssa wants to rent a car, knowing that
anygoal [31]

Answer:

400

Step-by-step explanation:

Car A costs 80d + 0.25m, where d is days and m is miles. Car B costs 100d + 0.10m. If you plug in 3 for d and make the equations equal, you get 240 + 0.25m = 300 + 0.10m. Combining like terms gives you 0.15m = 60, and dividing gives you m = 400.

4 0
3 years ago
How many hundreths are on 32.412?​
Elodia [21]

There are 4 hundredths or 4/100

3 0
4 years ago
Read 2 more answers
How can you determine if you divided the numbers correctly
Fittoniya [83]
Multiply them back into each other... You would multiply your answer with the number you  divided by (the number ouside the table if you used the table... ) and you should get the larger number you divided.
5 0
3 years ago
A statistics practitioner determined that the mean and standard deviation of a data set were 120 and 30, is respectively. What c
BartSMP [9]

Answer:

a) 68% of the observations lie between 90 and 150.

b) 95% of the observations lie between 60 and 180.

c) 99.7% of the observations lie between 30 and 210.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Standard deviation = 120

Mean = 30

a. 90 and 150

This is within 1 standard deviation of the mean.

By the Empirical Rule, 68% of the observations lie between 90 and 150.

b. 60 and 180

This is within 2 standard deviations of the mean.

By the Empirical Rule, 95% of the observations lie between 60 and 180.

c. 30 and 210

This is within 3 standard deviations of the mean.

By the Empirical Rule, 99.7% of the observations lie between 30 and 210.

4 0
3 years ago
Draw 8 lines that are between 1 inch and 3 inches long. Measure each line to the nearest fourth inch, and make a line plot
hammer [34]
--------------------------------                                                                                        --------------------------------
3 0
3 years ago
Read 2 more answers
Other questions:
  • Van uses 3/4 of a gallon of gas every 15 miles. How much gas does it use every 60 miles?
    7·1 answer
  • SWOT analysis refers to A. ​support, opportunities,​ weaknesses, and threats. B. ​strengths, opponents,​ weaknesses, and threats
    7·2 answers
  • What is the x intercept for y=x2+5x+6?!?!
    11·1 answer
  • Use substitution to solve the system of equations.
    11·1 answer
  • A ship traveled at an average rate of 25 miles per hour going west. It then traveled at an average rate of 19 miles per hour hea
    9·2 answers
  • What is the ratio cos C?
    5·2 answers
  • Which student correctly translated the phrase "twice the sum of a number cubed and nine" and evaluated it for r = 3?
    10·2 answers
  • Use the distributive property to rewrite each algebraic expression 7(y+2) + (8+r) + 8(x + 9)
    10·1 answer
  • Find an equation for the perpendicular bisector of the line segment whose endpoints are (−3,4) and (−7,−6).
    9·2 answers
  • I need help with this
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!