The Solution:
Given:
Center = (0,0)
Point A = (-5,2) being a point on the circle.
We are required to check if point P = (2,-5) is on the circle.
Solving the given problem graphically, we have:
From the above graph, it is clear that point P(2,-5) is a point on the circle.
The value of x such that f(x) = g(x) is x = 3
<h3>Quadratic equation</h3>
Given the following expressions as shown
f(x) = x^3-3x^2+2 and;
g(x) = x^2 -6x+11
Equate the expressions
x^3-3x^2+2 = x^2 -6x+11
Equate to zero
x^3-3x^2-x^2+2-11 = 0
x^3-3x^2-x^2 + 6x - 9 = 0
x^3-4x^2+6x-9 = 0
Factorize
On factorizing the value of x = 3
Hence the value of x such that f(x) = g(x) is x = 3
Learn more on polynomial here: brainly.com/question/2833285
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Answer:
24/4
Step-by-step explanation:
all you have to do is multiply 4x6=24
7-5*14=62
The equation above is how you would write it with a variable.
The number is 14.
This is because if you do 14 times 5, the answer is 70. Then If you subtract from that, it would be 62.
You can also do 62+7, which is 70, and then divide that by 5 and you will still get 14.
