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Usimov [2.4K]
3 years ago
15

1+1

Mathematics
2 answers:
aalyn [17]3 years ago
8 0

Answer: 2

Step-by-step explanation:

kipiarov [429]3 years ago
5 0
Answer is 2 ksjdhejdjdbdjdjdjdhdhd
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Suppose a tub has the shape of an elliptical paraboloid given by z = ax2+by2 (where a, b are some positive constants). If a marb
Umnica [9.8K]

Answer:

It would roll in this direction.

\nu  =  (-a/\sqrt{a^2+b^2},-b/\sqrt{a^2+b^2})

Step-by-step explanation:

It would roll to the direction of maximum decrease, which is the -1 times the direction of maximum increase, which is given by the gradient of the function.  

Since  

z =  ax^2  + by^2

For this case, the gradient of your function would be

\nabla z  = (2ax , 2by)

And  -1  times the gradient of your function would be

-\nabla z  = (-2ax , -2by)\\

Then, at

 (1,1,a+b),\\x = 1 \\y = 1

So it would go towards

v = (-2a,-2b)

The magnitud of that vector is

|v| =  2\sqrt{a^2+b^2}

and to conclude it would roll in this direction.

\nu  =  (-a/\sqrt{a^2+b^2},-b/\sqrt{a^2+b^2})

6 0
3 years ago
16. Which of the following measures can be determined for quantitative data?
Delvig [45]

Answer: D all of the above

Step-by-step explanation:

3 0
4 years ago
Plz help me!!!!!!!!!
Over [174]

Answer:  \bold{\dfrac{4\pm \sqrt{6}}{2}}

<u>Step-by-step explanation:</u>

\dfrac{3}{y-2}-2=\dfrac{1}{y-1}\\\\\\\text{Multiply by the LCD (y-2)(y-1) to clear the denominator:}\\\\\dfrac{3}{y-2}(y-2)(y-1)-2(y-2)(y-1)=\dfrac{1}{y-1}(y-2)(y-1)\\\\\\3(y-1)-2(y-2)(y-1)=1(y-2)\\\\3y-3-2(y^2-3y+2)=y-2\\\\3y-3-2y^2+6y-4=y-2\\\\-2y^2+9y-7=y-2\\\\0=2y^2-8y+5\quad \rightarrow \quad a=2,\ b=-8,\ c=5\\\\\\\text{Quadratic formula is: }x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\\x=\dfrac{-(-8)\pm \sqrt{(-8)^2-4(2)(5)}}{2(2)}\\\\\\.\ =\dfrac{8\pm \sqrt{64-40}}{2(2)}

.\ =\dfrac{8\pm \sqrt{24}}{2(2)}\\\\\\.\ =\dfrac{8\pm 2\sqrt{6}}{2(2)}\\\\\\.\ =\dfrac{4\pm \sqrt{6}}{2}

7 0
3 years ago
What is 7(2n+3) simplified without parenthesis
iVinArrow [24]
14n + 21



Just distribute the 7 to the 2n and the 3.

7(2n + 3)

(7 * 2n) + (7 * 3)

14n + 21



Please consider marking this answer as Brainliest to help me advance.
8 0
3 years ago
Read 2 more answers
there are two boxes. in the first box there are 7 cards numbered from 1 tp 7 the second box also contains 7 cards from 1-7 pick
mrs_skeptik [129]

Answer:

\frac{6}{49}

Step-by-step explanation:

GIVEN: There are two boxes. in the first box there are 7 cards numbered from 1 to 7 the second box also contains 7 cards from 1-7 pick one card from each box.

TO FIND: probability that the sum of the two two cards is at least 12.

SOLUTION:

sample case such that sum of cards is 12 : (5,7),(7,5),(6,6)

sample case such that sum of cards is 13 : (7,6),(6,7)

sample case such that sum of cards is 14 : (7,7)

Total sample case such that sum is atleast 12 =6

Total sample cases=49

probability that the sum of the two two cards is at least 12=\frac{\text{sample case in which sum is atleast 12}}{\text{total sample cases}}

=\frac{6}{49}

probability that the sum of the two two cards is at least 12 is \frac{6}{49}

8 0
3 years ago
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