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trapecia [35]
3 years ago
8

Math help please? w/ only two questions.

Mathematics
1 answer:
Law Incorporation [45]3 years ago
3 0
Maybe: 1. When I play basketball i wear cletes. 2. If a quadrilateral figure has four right angles then it is a square <span> </span> my best guess. Let me know if it helps
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Drawing Conclusions
maksim [4K]

Answer:

Some of the Exponents = -2 that is true, not 2.

Step-by-step explanation:

Let's check one at a time.

(a)The 6 without an exponent is equivalent to the 6 having a 0 exponent.

6^{0} =1 and 6^{1} = 6 (no exponent. 6 \neq 1 therefore this statement is False.

(b)The sum of the exponents is -2.

let's check , if the base is same we can add the exponents that is the exponent rule.(well established).

if we add exponents in the given expression we get.

6^{1} 6^{0} 6^{3} =6^{1+0+(-3)} =6^{-2}, therefore we can see that the sum of the exponents = -2 this is true.

(c) An equivalent expression is 65.6-7, lets evaluate our above expression, it is equal to \frac{1}{36} which we can see that \frac{1}{36}  \neq 65.6-7 ,therefore this statement is false as well.

3 0
3 years ago
Mrs.Hernandez told her class that 95% of the students in the class passed the math test if there are 20 students in the class ho
disa [49]

Answer:

19 people passed

Step-by-step explanation:

19 people passed the test

6 0
3 years ago
Explain how the distance formula can prove Pythagoras' Theorem. In your
Paul [167]

Answer:

Given a triangle ABC, Pythagoras' Theorem shows that:

c^2=a^2+b^2

Thus,

c = \sqrt{a^2+b^2}

The distance formula, gives an equivalent expression based on two points at the end of the hypotenuse for a triangle.

d^2 = (x_{2} -x_{1})^2 + (y_{2} -y_{1})^2

d = \sqrt{(x_{2}-x_{1})^2 +  (y_{2} -y_{1})^2 }

Therefore when given the hypotenuse with endpoints at

(x_{1}, y_{1})  and {(x_{2}, y_{2})

We know that the third point of the right triangle will be at

(x_{2}, y_{1})

and that the two side lengths will be defined by the absolute values of:

(x_{2} - x_{1}) = a

(y_{2} - y_{1}) = b

8 0
2 years ago
If y=-4+11 and 3x+y=9 what is the value of y?
liubo4ka [24]

Answer:

y = 7

x = 2/3

Step-by-step explanation:

hope it help

plz follow me

8 0
3 years ago
Read 2 more answers
Value of x-y^x-y when x=2 and y=-2?​
Nonamiya [84]

Step-by-step explanation:

x-y^x-y

2-(-2)^2-(-2)

2-(-2)^2+2

2-(-2)^4

2-(16)

=-14

3 0
2 years ago
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