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Mashutka [201]
3 years ago
9

Find the difference. express your answer in simplest form. (2s/s^2-4s+4) - (4/s^2-4s+4)

Mathematics
2 answers:
LUCKY_DIMON [66]3 years ago
5 0
To find the difference, we are going to destroy the parenthesis first, and then, we are going to perform the operations. Remember that to destroy a parenthesis preceded by a negative sign (-), you should change the signs of the factors inside the parenthesis:
\frac{2s}{s^2-4s+4} -( \frac{4}{s^2-4s+4} )
\frac{2s}{s^2-4s+4} -\frac{4}{s^2-4s+4}= \frac{2s-4}{s^2-4s+4}

Now we can factor both numerator and denominator and simplify:
\frac{2s-4}{s^2-4s+4} = \frac{2(s-2)}{(s-2)^2} = \frac{2}{s-2}

We can conclude that the difference in simplest form is: \frac{2}{s-2}
Phantasy [73]3 years ago
4 0
To get started, combine <span>-4s+4 with 4s - 4.  Result:  0.  That leaves

 2s        4          2(s+2)
------ - ------- = ------------
s^2      s^2           s^2</span>
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