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Naya [18.7K]
3 years ago
12

What is the answer to(1−5q)+2(2.5q+8)

Mathematics
1 answer:
never [62]3 years ago
5 0
Greetings!

Simplify the Expression.
=(1-5q)+2(2.5q+8)

Distribute the Parenthesis. 
<em>How?</em><span> Multiply the terms inside the Parenthesis by the term outside of the Parenthesis.
</span>=1*1-1*5q+2*2.5q+2*8

Combine Like Terms.
=1-5q+5q+16

=17

The Answer Is:
\left[\begin{array}{ccc}17\end{array}\right]

Hope this helps.
-Benjamin

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!
Darina [25.2K]

The graph of the equations was plotted using geogebra graphing and attached.

Let x represent the hours weightlifting and y represent the hours doing cardio exercises.

Since he spend a maximum of 20 hours, hence:

x + y ≤ 20   (1)

Also, he spends at least 8 of those hours weightlifting, hence:

x ≥ 8          (2)

He wants to spend no more than 15 hours doing cardio exercises, this is:

y ≤ 15     (3)

The graph of the equations was plotted using geogebra graphing and attached.

Find out more at: brainly.com/question/17178834

3 0
3 years ago
What is 6x+78/67-78x=180+270-567
Sonja [21]

Answer:

15.31

Step-by-step explanation:

solve both sides separately

6x+78/67-78x

x cancles out

becomes 84/-11

becomes -7.64 rounded

180+270-567

becomes -117

moves -7.64 to other side (divide by other side)

-117/-7.64

becomes 15.31

8 0
2 years ago
Factor 4a2 - 25.<br><br> A. (2a + 5)(2a + 5)<br> B. (2a - 5)(2a - 5)<br> C. (2a - 5)(2a + 5)
nikdorinn [45]

This is the diference of 2 perfect squares. 4 is a perfect square, x^2 is a perfect square, and 25 is a perfect square. The pattern for this is (ax + b)(ax - b). Our a is 2 since 2*2 = 4, and our b is 5 since 5*5 = 25. So your factors are (2a+5)(2a-5), choice C.

3 0
3 years ago
Given the functions below, find g(5) + h(2).<br> g(x) = 2x - 5<br> h(x) = 4x + 5
Ksju [112]
G(5) = 2(5)-5=5
h(2)=4(2)+5=13

So, g(5)+h(2)=13+5=18.
4 0
2 years ago
Read 2 more answers
Ill give you brainliest pleaseeeeeeee help me
ruslelena [56]
Line D and C because they are not parallel but distorted or unsymmetrical
4 0
4 years ago
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