Question

HELP asap plz Solve 2y^2 – 3y = 2

Answer 1

Your answer is y = -1/2 and y = 2

To solve this quadratic we first need to subtract 2 from both sides to set it equal to 0, which gives us 2y² - 3y - 2 = 0

Then we just need to factorise it:

2y² - 3y - 2 = 0
(2y + 1)(y - 2) = 0

Now we can set each bracket equal to 0 and solve for y:
2y + 1 = 0
2y = -1
y = -1/2

y - 2 = 0
y = 2

I hope this helps! Let me know if you have any questions :)