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Maru [420]
3 years ago
5

HELP asap plz Solve 2y^2 – 3y = 2

Mathematics
1 answer:
Veseljchak [2.6K]3 years ago
7 0
Your answer is y = -1/2 and y = 2

To solve this quadratic we first need to subtract 2 from both sides to set it equal to 0, which gives us 2y² - 3y - 2 = 0

Then we just need to factorise it:

2y² - 3y - 2 = 0
(2y + 1)(y - 2) = 0

Now we can set each bracket equal to 0 and solve for y:
2y + 1 = 0
2y = -1
y = -1/2

y - 2 = 0
y = 2

I hope this helps! Let me know if you have any questions :)
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The area of the rectangular-shaped building is 2448 square feet.

<h3>What is the area of the rectangle?</h3>

The space occupied by any two-dimensional figure in a plane is called the area. The space occupied by the rectangle in a two-dimensional plane is called the area of the rectangle.

Given that a rectangular-shaped building that is 34 feet wide and 72 feet long. The area of the rectangle will be calculated as below:-

Area of rectangle = Length x width

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