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Eddi Din [679]
4 years ago
8

The sum of two numbers is 24. One is 6 less than twice the other. Find the two numbers.

Mathematics
1 answer:
Fynjy0 [20]4 years ago
6 0

Answer:

\huge\boxed{\sf x = 14 , y = 10}

Step-by-step explanation:

Let the two numbers be x and y

<u>Condition # 1:</u>

<h2>x + y = 24  ---------------------(1)</h2>

<u>Condition # 2:</u>

<h2>x = 2y - 6  ----------------------(2)</h2>

\rule[225]{225}{2}

Putting Equation # 2 in Equation # 1

2y - 6 + y = 24

3y - 6 = 24

Adding 6 to both sides

3y = 24 + 6

3y = 30

Dividing both sides by 3

y = 10

\rule[225]{225}{2}

Putting y = 10 in Equation # 2

x = 2y - 6

x = 2(10) - 6

x = 20 - 6

x = 14

\rule[225]{225}{2}

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Work out the following, giving your answers in their simplest form: 4 2/5 ÷ 1 1/5
Black_prince [1.1K]

Answer:

First make mixed

4 x 5 = 20

20 + 2 = 22

22/5 = 4 2/5

1 x 5 = 5

5 + 1 = 6

6/5= 1 1/5

Multiply the reciprocal. The reciprocal is the fraction flipped over like 1/2 becomes 2/1

22/5 / 6/5 = 22/5  x 5/6

Multiply

22 x 5 = 110

5 x 6 = 30

110/30

Simplify

110/10=11

30/10=3

Answer is

11/3 = 3 2/3

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Which equation is represented by the table?
MatroZZZ [7]

Answer:

y=-|x-3|-3

Step-by-step explanation:

The table shows values of y for different values of x.

Let us test each equation with the values given in the table.

Equation 1: y=|x+3|-3

For x = 1, we get,

y=|x+3|-3=|1+3|-3=|4|-3=4-3=1

So, we got 1 for y. But as per table, value of y should be -5.

So, equation 1 is incorrect.

Equation 2: y=-|x-3|-3

For x = 1, we get,

y=-|x-3|-3=-|1-3|-3=-|-2|-3=-(2)-3=-5

So, we got -5 for y. It matches with the value of table.

Let us check for another value of x in order to confirm.

For x =2, we get,

y=-|x-3|-3=-|2-3|-3=-|-1|-3=-(1)-3=-4

So, we got -4 for y. It matches with the value of table.

So, equation 2 is the correct answer.

We can be completely sure by checking the remaining equations too.

Equation 3: y=|x-3|-3

For x = 1, we get,

y=|x-3|-3=|1-3|-3=|-2|-3=2-3=-1

So, we got -1 for y. But as per table, value of y should be -5.

So, equation 3 is incorrect.

Equation 4: y=-|x+3|-3

For x = 1, we get,

y=-|x+3|-3=-|1+3|-3=-|4|-3=-4-3=-7

So, we got -7 for y. But as per table, value of y should be -5.

So, equation 4 is incorrect.

3 0
3 years ago
In Mrs. Johnson's class there are 28 student desks each desk measures 26.17 inches long if you were to line up all the desks end
just olya [345]
If you were to line them all up:

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4 0
3 years ago
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Step-by-step explanation:

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8 0
2 years ago
Read 2 more answers
2a + 4b + c =5 <br> x =-2 <br><br> a - 4b = -6<br> y=1
cricket20 [7]
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// Solve equation [3] for the variable  c  
 

<span> [3] c = -a + 2b - 5 </span>

// Plug this in for variable  c  in equation [1]

<span><span>  [1] 2a + (-a +2?-5) = -10 </span><span>  [1] a = -5 </span></span>

// Plug this in for variable  c  in equation [2]

<span><span>  [2] - (-? +2b-5) + b = 15 </span><span>  [2] - b = 10 </span></span>

// Solve equation [2] for the variable  ?  
 

<span> [2] ? = b + 10 </span>

// Plug this in for variable  ?  in equation [1]

<span><span>  [1] (? +10) = -5 </span><span>  [1] 0 = -15 => NO solution </span></span><span>No solution</span>
3 0
3 years ago
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