We know that equation of a parabola is given by :-
y = a(x-h)² + k
Where (h,k) is the vertex of parabola and (x,y) is any point on its curve.
Given that vertex of parabola is (3,5) and one point (x,y) is (6,-1).
We can plug the given information in the equation of parabola and solve it for value of 'a' :-
-1 = a(6 - 3)² + 5
-1 = a(3)² + 5
-1 = 9a + 5
9a = -1 -5 = -6
a = 
a = 
is the final answer.
Answer:
1. -100
2. -75
3. -18
Step-by-step explanation:
Answer:
See attachment
Step-by-step explanation:
We want to graph the system
2x+y=8
-x+2y=6
Let us rewrite the lines in slope intercept form:
y=-2x+8
The first line has a slope of -2 and a y-intercept of 8
The second line has a slope of 1/2 and a y-intercept of 3
We can no graph the lines as shown in the attachment.
Answer:
1. x = 10
2. x = 4
Step-by-step explanation:
I use the angle ABC method:
AB² + AC² = BC²
6² + 8² = x²
x = 10
AB² + AC² = BC²
3² + x² = 5²
x = 4
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Answer:
It is CD
Step-by-step explanation:
because 300+200=500, juts times it by 3 and divide
