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MaRussiya [10]
3 years ago
9

Calculus help please!!! Click the link to see the integral.

Mathematics
1 answer:
iren [92.7K]3 years ago
3 0
Noice

ook, so use u subsitution

remember that dy/dx(sin(x))=cos(x)

u=sin(x)
du/dx=cos(x)
du=cos(x) dx
so then

\int\limits{ \frac{cos(x)}{ \sqrt{sin(x)} } } \, dx
replace
\int\limits{ \frac{1}{ \sqrt{u} } } \, du
we do some stuff
\int\limits{ u^ \frac{-1}{2}  } } \, du
\frac{u^ \frac{1}{2} }{ \frac{1}{2} }
2 \sqrt{u}
u=sin(x)
2 \sqrt{sin(x)}
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