Question

Form a polynomial whose real zeros and degree. zeros: -3,0,2: Degree 3

Answer 1

Answer:

The polynomial is $x^3 + x^2-6x$.

Explanation:

Given:

Real zeros: -3,0,2

Degree 3

To Find:

The polynomial

Solution:

Now, according to given information, x = -3, x = 0 and x = 2 are zeros of equation.

Then, x – (-3) x + 3, x and x – 2 are the factors of the equation.

Now, multiply the factors, such that we will get equation.  

x(x + 3)(x – 2)  

$x(x^2 + 3-2x- 6)$

$x(x^2+ x-6)$

$x^3 + x^2-6x$