1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
musickatia [10]
4 years ago
7

How do I solve this problem?

Mathematics
1 answer:
nexus9112 [7]4 years ago
5 0
Subtract the second equation from the first equation.
x = -1
Plug -1 back in to either equation and solve for y.
3(-1) + y =-10
-3 + y = -10
Add 3 to both sides
y = -7
CHECK
3(-1) -7 = -10
2(-1) -7 = -9
(-1, -7)
You might be interested in
Find the surface area of the cylinder 6cm 6cm <br> Give your answer in terms of pi
Lisa [10]

Answer:  A=2πrh+2πr2

Hope this helps you out! :}


4 0
3 years ago
Read 2 more answers
For which pair of numbers is 7 the greatest common factor (GCF)?
Elanso [62]

Answer:

B cuz both can be divided by 7

5 0
3 years ago
1. Solve the equation.<br>4(x + 5) = 24<br><br>​
bixtya [17]

Answer:

x=1

Step-by-step explanation:

4(x+5)= 24

4x+20=24

-20 -20

____________

4x = 4

___ ____

4 4

x= 1

7 0
4 years ago
Read 2 more answers
Evaluate c-2 when c =7
LenaWriter [7]
If C = 7, You would do 7-2 = 5
5 0
3 years ago
Read 2 more answers
A survey of athletes at a high school is conducted, and the following facts are discovered: 13% of the athletes are football pla
nekit [7.7K]

Answer:

The probability that an athlete chosen is either a football player or a basketball player is 56%.

Step-by-step explanation:

Let the athletes which are Football player be 'A'

Let the athletes which are Basket ball player be 'B'

Given:

Football players (A) = 13%

Basketball players (B) = 52%

Both football and basket ball players = 9%

We need to find probability that an athlete chosen is either a football player or a basketball player.

Solution:

The probability that athlete is a football player = P(A)= \frac{13}{100}=0.13

The probability that athlete is a basketball player = P(B)= \frac{52}{100}=0.52

The probability that athlete is both basket ball player and  football player = P(A\cap B) = \frac{9}{100}=0.09

We have to find the probability that an athlete chosen is either a football player or a basketball player P(A\cup B).

Now we know that;

P(A\cup B)= P(A) + P(B) - P(A \cap B)\\\\P(A\cup B) = 0.13+0.52-0.09=0.56\\\\P(A\cup B) = \frac{0.56}{100}=56\%

Hence The probability that an athlete chosen is either a football player or a basketball player is 56%.

5 0
4 years ago
Other questions:
  • What error did she make? She simplified the denominator incorrectly. The denominator simplifies to –7. She labeled the points in
    13·2 answers
  • Help ITS DUE Tomorrow!!!!!!!!
    8·1 answer
  • Find value of x<br> (2x+7)=(3x-52)
    5·2 answers
  • So i need help on one of my homework questions. The problem is, On his first 2 tests Nate`s average score was 80 percent. On his
    12·1 answer
  • How do u multiply fractions
    6·1 answer
  • What does the expression l∙w represent
    8·1 answer
  • Please answer each question truthfully or I will report you
    12·2 answers
  • Hannah works at an electronics store as a salesperson. Hannah earns a 7% commission on the total dollar amount of all phone sale
    14·1 answer
  • Andre’s group was asked to write an expression equivalent to 5 p squared q + 7 p q squared minus 10. When Ms Berger checked thei
    11·2 answers
  • A landscaping service company charges customers a one-time fee and an hourly rate of $15. For 1 hour of service, the company cha
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!