Step-by-step explanation:
Permutation
:The number of ways to choose a sample of r elements from a set of n distinct objects where order does matter and replacements are not allowed.
Factorial
: There are n! ways of arranging n distinct objects into an ordered sequence.
Considering a situation when n = r in a permutation, nPr reduces to n!, a simple factorial of n.
Proof: 3P3 = 3!
n = 3 and r = 3
But 0! = 1
3P3 = 3!
Answer: y ≥ (3/5)*x - 3
Step-by-step explanation:
In the graph, we can see that we are above a bold line, that goes through the points (0, -3) and (5, 0)
First, let's find the equation for this line:
y = a*x + b
the value of a is the slope and is equal to:
a = (0 - (-3))/(5 -0) = 3/5
and the value of b is the point where the line intersects the y-axis, in this case, b = -3
then our line is
y = (3/5)*x - 3
As the shaded part is above the line, this equality represents the minimum value that y can take for a given x, and because the line is not a doted line, we know that the equality is valid, so we must use the ≥ symbol.
y ≥ (3/5)*x - 3
Answer:
352 ft²
Step-by-step explanation:
The formula for the area of a trapezoid is 
where 
and 
are the bases of the trapezoid and 
is the height, thus:
This means that the area of the trapezoid is 352 ft².
The cosine of an angle is the x-coordinate of the point where its terminal ray intersects the unit circle. So, we can draw a line at x=-1/2 and see where it intersects the unit circle. That will tell us possible values of θ/2.
We find that vertical line intersects the unit circle at points where the rays make an angle of ±120° with the positive x-axis. If you consider only positive angles, these angles are 120° = 2π/3 radians, or 240° = 4π/3 radians. Since these are values of θ/2, the corresponding values of θ are double these values.
a) The cosine values repeat every 2π, so the general form of the smallest angle will be
... θ = 2(2π/3 + 2kπ) = 4π/3 + 4kπ
b) Similarly, the values repeat for the larger angle every 2π, so the general form of that is
... θ = 2(4π/3 + 2kπ) = 8π/3 + 4kπ
c) Using these expressions with k=0, 1, 2, we get
... θ = {4π/3, 8π/3, 16π/3, 20π/3, 28π/3, 32π/3}
