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ahrayia [7]
3 years ago
6

Determine which functions have two real number zeros by calculating the discriminant, b2 – 4ac. Check all that apply.

Mathematics
1 answer:
pantera1 [17]3 years ago
5 0

Step-by-step explanation:

We need to write the function that have two real number zeros by calculating the discriminant i.e. b^2-4ac.

We know that,

If D>0  the roots are real and unequal

If D= 0 roots are real and equal

If D< 0 roots are imaginary or not real and unequal

Function (1)

f(x)=x^2 + 6x + 8\\\\D=6^2-4\times 1\times 8\\\\D=4

D>0  the roots are real and unequal

Function (2)

g(x)=x^2 + 4x + 8\\\\D=4^2-4\times 1\times 8\\\\D=-16

D<0  the roots are real and unequal

Function (3)

h(x)=x^2 -12x+32\\\\D=(-12)^2-4\times 1\times 32\\\\D=16

D>0  the roots are real and unequal

Function (4)

k(x)=x^2 +4x-1\\\\D=(4)^2-4\times 1\times (-1)\\\\D=20

D>0  the roots are real and unequal

Function (5)

p(x)=5x^2 +5x+4\\\\D=(5)^2-4\times 5\times 4\\\\D=-55

D<0  the roots are real and unequal

Function (6)

t(x)=x^2 -2x-15\\\\D=(-2)^2-4\times 1\times (-15)\\\\D=64

D>0  the roots are real and unequal

(1),(3),(4) and (6) have two real number zeroes.

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Option C: 38 is p more than 25

Step-by-step explanation:

the equation 25 + p = 38

can be read as 38 is 25 plus p units, or similarly ;

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Find the values of x and y that satisfy the equation.
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x=-5-2yi/3+4i

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5 0
3 years ago
You have been asked to design a can shaped like right circular cylinder that can hold a volume of 432π-cm3. What dimensions of t
rosijanka [135]

Answer:

Height = 12cm

Radius = 6cm

Step-by-step explanation:

Given

Represent volume with v, height with h and radius with r

V = 432\pi

Required

Determine the values of h and r that uses the least amount of material

Volume is calculated as:

V = \pi r^2h\\

Substitute 432π for V

432\pi = \pi r^2h

Divide through by π

432 = r^2h

Make h the subject:

h = \frac{432}{r^2}

Surface Area (A) of a cylinder is calculated as thus:

A=2\pi rh+2\pi r^2

Substitute \frac{432}{r^2} for h in A=2\pi rh+2\pi r^2

A=2\pi r(\frac{432}{r^2})+2\pi r^2

A=2\pi (\frac{432}{r})+2\pi r^2

Factorize:

A=2\pi (\frac{432}{r} + r^2)

To minimize, we have to differentiate both sides and set A' = 0

A'=2\pi (-\frac{432}{r^2} + 2r)

Set A' = 0

0=2\pi (-\frac{432}{r^2} + 2r)

Divide through by 2\pi

0= -\frac{432}{r^2} + 2r

\frac{432}{r^2} = 2r

Cross Multiply

2r * r^2 = 432

2r^3 = 432

Divide through by 2

r^3 = 216

Take cube roots of both sides

r = \sqrt[3]{216}

r = 6

Recall that:

h = \frac{432}{r^2}

h = \frac{432}{6^2}

h = \frac{432}{36}

h = 12

Hence, the dimension that requires the least amount of material is when

Height = 12cm

Radius = 6cm

3 0
3 years ago
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