the Pythagorean Theoremproof of let ΔABC be a right triangle. and sinA=a/c, and cosA= b/ca opposite side of the angle Ab the adjacent side of the angle Aand c is the hypotenuswe know that sin²A +cos²A= (a/c)²+ (b/c) ², but sin²A +cos²A=1so, a²/c²+ b²/c ²=1 which implies a²+ b²=c² the answer is Transitive Property of Equality proof the right triangles BDC and CDA are siWe start with the original right triangle, now denoted ABC, and need only one additional construct - the altitude AD. The triangles ABC, DBA, and DAC are similar which leads to two ratios:AB/BC = BD/AB and AC/BC = DC/AC.Written another way these becomeAB·AB = BD·BC and AC·AC = DC·BCSumming up we getAB·AB + AC·AC= BD·BC + DC·BC = (BD+DC)·BC = BC·BC.so not in the proof is Transitive Property of Equality
Angle Angle Side. The side is given to you and use the interior angle to find one angle, and the the reflexive property to find the other.
Legs with "B" in their title can not be opposite to the angle B, as they are touching it. So...
The opposite leg to the angle B is the leg AC.
9514 1404 393
Answer:
a) $42.35
b) $5124.56
c) $407.44
Step-by-step explanation:
a) The interest due is that for one month on the remaining balance:
I = Prt
I = $5082.21·0.10·1/12 = $42.35
__
b) The final payment is ...
$5082.21 +42.35 = $5124.56
__
c) Had Hudson continued paying, he would have paid ...
20·$276.60 = $5532.00
So, he saved ...
$5232.00 -5124.56 = $407.44
Answer: 71
Step-by-step explanation: A triangle adds up to 180 so you subtract 28 and 81 from 180 to get your answer
