Ask question

Ask question

All categories

3 years ago

6

In a natural population of bugs living on balloon vine in Baton Rouge, Louisiana, female beak length ranged from 6.5 to 9.5 mm w

ith a mean at 8 mm. How well does this distribution fit your expectation

1 answer:

sp2606 [1]3 years ago

4 0

Answer:

This distribution mostly fit my expectation but the beak length of 6.5mm size may not able to reach the seed

You might be interested in

What does it mean for a function to have a root?

ZanzabumX [31]

Answer:

Step-by-step explanation:

A function has a root when it crosses the x-axis, i.e. . A function can have more than one root, when there are multiple values for that satisfy this condition. The goal is to find all roots of the function (all values). In general we take the function definition and set to zero and solve the equation for .

3 0

3 years ago

Read 2 more answers

The average of six positive integers starting with a is equal to b. What is the average of five consecutive integers ending with

kvasek [131]

The average of the five consecutive numbers ending with b in discuss when expressed in terms of a is; Choice D; a+3.

<h3>What is the average of five consecutive integers ending with b?</h3>

First, since it was given in the task content that the average of six positive consecutive odd integers starting with a is equal to b, it therefore follows that;

(a+a+2+a+4+a+6+a+8+a+10)/6 = b

6b=6a+30

b=a+5

Also, let the average of the consecutive intergers ending with b be denoted by; x.

(b+b-1+b-2+b-3+b-4)/5 = x

=(5b-10)/5

=b–2

The average, x=b – 2 (where b = a-5)

Ultimately, the value of the required average is; = a+5-2 = a+3.

Read more on average of integers;

brainly.com/question/24369824

#SPJ1

7 0

1 year ago

*URGENT* 40 POINTS<br> Determine the measure of angle ESA in the circle below. <br> Explain.

AnnyKZ [126]

Its 70 because it is

7 0

3 years ago

7(xy) equivalent expression

mariarad [96]

Answer:

Espero te sirva

Step-by-step explanation:

Good bye

6 0

3 years ago

Use lagrange multipliers to find the shortest distance, d, from the point (4, 0, −5 to the plane x y z = 1

Varvara68 [4.7K]

I assume there are some plus signs that aren't rendering for some reason, so that the plane should be $x+y+z=1$ .

You're minimizing $d(x,y,z)=\sqrt{(x-4)^2+y^2+(z+5)^2}$ subject to the constraint $f(x,y,z)=x+y+z=1$ . Note that $d(x,y,z)$ and $d(x,y,z)^2$ attain their extrema at the same values of $x,y,z$ , so we'll be working with the squared distance to avoid working out some slightly more complicated partial derivatives later.

The Lagrangian is

$L(x,y,z,\lambda)=(x-4)^2+y^2+(z+5)^2+\lambda(x+y+z-1)$

Take your partial derivatives and set them equal to 0:

$\begin{cases}\dfrac{\partial L}{\partial x}=2(x-4)+\lambda=0\\\\\dfrac{\partial L}{\partial y}=2y+\lambda=0\\\\\dfrac{\partial L}{\partial z}=2(z+5)+\lambda=0\\\\\dfrac{\partial L}{\partial\lambda}=x+y+z-1=0\end{cases}\implies\begin{cases}2x+\lambda=8\\2y+\lambda=0\\2z+\lambda=-10\\x+y+z=1\end{cases}$

Adding the first three equations together yields

$2x+2y+2z+3\lambda=2(x+y+z)+3\lambda=2+3\lambda=-2\implies \lambda=-\dfrac43$

and plugging this into the first three equations, you find a critical point at $(x,y,z)=\left(\dfrac{14}3,\dfrac23,-\dfrac{13}3\right)$ .

The squared distance is then $d\left(\dfrac{14}3,\dfrac23,-\dfrac{13}3\right)^2=\dfrac43$ , which means the shortest distance must be $\sqrt{\dfrac43}=\dfrac2{\sqrt3}$ .

7 0

3 years ago