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3 years ago

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Abigail needs at least $199 to purchase the new phone that she wants. Last week she babysat and earned $45. Write and solve an i

nequality to find m, the amount of money Abigail needs to meet her goal.

1 answer:

Anon25 [30]3 years ago

5 0

Answer: she needs to babysit 4 more times.

Step-by-step explanation:

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Emma has $89 in her bank account. she uses 30% of her money to pay a bill. How much did she spend?

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The answer is c 10% of 89 is 8.9 so multiply by 3 you get 26.70

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Mr . Bernstein teaches 100studens. of his 100studwnts ,21wear glasses . what percent of me Bernstein 's students wear glasses

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21% of his students wear glasses

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2 years ago

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2 years ago

The 2nd, 6th, 8th terms of an A.P. form a G.P. , find the common ratio and the general term of the G.P.

melisa1 [442]

The terms of an arithmetic progression, can form consecutive terms of a geometric progression.

The common ratio is: $\mathbf{r = \frac{a + 5d}{a + d}}$
The general term of the GP is: $\mathbf{a_n = (a + d) \times (\frac{a + 5d}{a + d})^{n-1}}$

The nth term of an AP is:

$\mathbf{T_n = a + (n - 1)d}$

So, the <em>2nd, 6th and 8th terms </em>of the AP are:

$\mathbf{T_2 = a + d}$

$\mathbf{T_6 = a + 5d}$

$\mathbf{T_8 = a + 7d}$

The <em>first, second and third terms </em>of the GP would be:

$\mathbf{a_1 = a + d}$

$\mathbf{a_2 = a + 5d}$

$\mathbf{a_3 = a + 7d}$

The common ratio (r) is calculated as:

$\mathbf{r = \frac{a_2}{a_1}}$

This gives

$\mathbf{r = \frac{a + 5d}{a + d}}$

The nth term of a GP is calculated using:

$\mathbf{a_n = a_1r^{n-1}}$

So, we have:

$\mathbf{a_n = (a + d) \times (\frac{a + 5d}{a + d})^{n-1}}$

Read more about arithmetic and geometric progressions at:

brainly.com/question/3927222

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3 years ago